Help!!! use gauss-jordan elimination to solve the following system of equations x + y + z =2

Mathematics

1 answer:

Stells [14]3 years ago

6 0

Your answer is A.

You already have a set of answers to choose from...all you really need to do is substitute those into the equation to get the answer. BUT you should definitely learn how to do this yourself, hun. Using Gauss-Jordan elimination.

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Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 134 millimeters,

Arisa [49]

; 134

a:8

n:44

3.6

P,ob.Z);Jlty : 1 - P(:

<z<-

[ - ]]p(-2.98 ' z ' 2.98)]

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3 years ago

Multiply and simplify the product. –12i × 3i Select the product. 36 -36 36i -36i

bazaltina [42]

Answer:

Step-by-step explanation:

–12i × 3i

Multiply the numbers

-12*3 = -36

Multiply the imaginary number

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4 years ago

Read 2 more answers

What the recursive formula for the sequence

klemol [59]

$\bf n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ d=\textit{common difference} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ a_n=2-5(n-1)\implies a_n=\stackrel{\stackrel{a_1}{\downarrow }}{2}+(n-1)(\stackrel{\stackrel{d}{\downarrow }}{-5})$

so, we know the first term is 2, whilst the common difference is -5, therefore, that means, to get the next term, we subtract 5, or we "add -5" to the current term.

$\bf \begin{cases} a_1=2\\ a_n=a_{n-1}-5 \end{cases}$

just a quick note on notation:

$\bf \stackrel{\stackrel{\textit{current term}}{\downarrow }}{a_n}\qquad \qquad \stackrel{\stackrel{\textit{the term before it}}{\downarrow }}{a_{n-1}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{current term}}{a_5}\qquad \quad \stackrel{\textit{term before it}}{a_{5-1}\implies a_4}~\hspace{5em}\stackrel{\textit{current term}}{a_{12}}\qquad \quad \stackrel{\textit{term before it}}{a_{12-1}\implies a_{11}}$