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3 years ago

9

Do you equation Y equals negative 7x -5 and another equation have a solution of (-2,9). Which of the following could be the seco

nd equation?
A. y= 1/2 + 10
B. y= 1/2x + 7
C. y= 3x-3
D. y=2x+5

1 answer:

djverab [1.8K]3 years ago

5 0

The answer is

A. y = 1/2x + 10

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What is the prime factorization of 54

nadya68 [22]

The prime factorization is 3.

Steps:

1. Break 54 into 2 parts, I broke them into 2 and 27.

2. Since 2 is prime, leave it as is and break 27 into 2. I got 3 and 9.

3. 3 is prime so leave it alone. Break 9 into 3 and get 3 and 3. Your prime factor is 3.

Now, you need the prime factorization, which, if I remember correctly, is the prime factors that you left and did not break apart. List these in order from least to greatest. Your prime factorization should end up looking like this:

2 x 3 x 3 = 54

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4 years ago

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3 years ago

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Step-by-step explanation:

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4 years ago

Read 2 more answers

A lighthouse is located on a small island 2 km away from the nearest point P on a straight shoreline and its light makes four re

ddd [48]

Answer:

62.8 km per min

Step-by-step explanation:

Let the diagram of this situation is shown below,

In which $\theta$ is the angle made by light to the straight line joining the lighthouse and P,

∵ Light makes 4 revolutions per minute.

Also, 1 revolution = $2\pi$ radians

So, the change in angle with respect to t ( time ),

$\frac{d\theta}{dt}=8\pi\text{ radians per min}$

Let x be the distance of beam from P,

$\implies \tan \theta = \frac{x}{2}$

Differentiating with respect to x,

$\sec^2 \theta \frac{d\theta}{dt}=\frac{1}{2}\frac{dx}{dt}$

$(1+\tan^2 \theta) (8\pi) = \frac{1}{2}\frac{dx}{dt}$

$(1+\frac{x^2}{2^2})(8\pi) = \frac{1}{2}\frac{dx}{dt}$

If x = 1 km,

$(1+\frac{1}{4})8\pi =\frac{1}{2}\frac{dx}{dt}$

$\frac{5}{4}8\pi = \frac{1}{2}\frac{dx}{dt}$

$\implies \frac{dx}{dt}=\frac{80\pi}{4}= 20\pi\approx 62.8\text{ km per min}$

Hence, the beam of light moving along the shoreline with the speed of 62.8 km per min

7 0

4 years ago

What is the product of 3 square root 7 and 17 square root 14 in simplest radical form

Aleks [24]

$3 \sqrt{7} \times 17 \sqrt{14}$

This is the problem that we need to solve. The best way to get about it is to first:

Multiply the constant numbers (3 and 17). 3×17 is 51.
Next multiply the radicals.
$\sqrt{7} \times \sqrt{14} = \sqrt{7 \times 14} = \sqrt{108}$
Simplify the squareroot of 108 since it is 49 times 2. It would be equal to 7 squareroots of 2.
Our final answer would be:
$51 \times 7\sqrt{2} = 357 \sqrt{2}$
51 x 7 is 357, so the answer above is right.

The skills needed are multiplication, mulitplication of radicals, and simplifying radicals, so if you want to review anything use these as reference.

Hope you understood and have a nice day!!

3 0

3 years ago