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pshichka [43]
3 years ago
14

Please help I’ll make you the brainiest

Mathematics
1 answer:
lakkis [162]3 years ago
6 0

Answer:

X= 5, -2

Step-by-step explanation:

This would be the answer if you are looking to "solve"

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Find the lateral area of the prism.<br> 4cm<br> 3cm <br> 6cm<br> 5cm<br> Lateral Area = [?]cm2
kolbaska11 [484]

Answer:

The lateral surface area of a prism is the sum of the surface areas of the sides of the prism.

Since the bases of the prism are triangles, there are three sides. The area of each lateral is the product of a side of the triangle times the height of the prism.

We can express this as Lateral Surface Area LSA = (s1xh) + (s2xh) + (s3+h), where "s1, s2, s3" are the lengths of the sides of the triangle and "h" is the height of the prism.

We can factor out "h" to get LSA = hx(s1+s2+s3) where the factor "s1+s2+s3" is the perimeter of the triangle.

Solving for "h", we get h = LSA / (s1+s2+s3)

For your specific problem, h = 300 / (4 + 5 + 6) = 300 / 15 = 20

4 0
2 years ago
It cost Evan $17.70 to send 177 text messages. How many text messages did he send if he spent $19.10?​
rusak2 [61]

Answer:

191

Step-by-step explanation:

The amount spent for a single text:  177/17,7=0,1

x×0,1=19,1

x=19,1/0,1

x=191

6 0
2 years ago
Please help answer!!!! <br> will try and give brainliest if i can.<br> need all four answers!
Ivahew [28]

Answer:

a is option c

b is 17.5

c is 9

Step-by-step explanation:

I do not know if all of these are right

6 0
3 years ago
What is the relationship between decimals and fractions
umka2103 [35]
A fraction you are dividing while a decimal is considered as a number
7 0
3 years ago
Problem 8-4 A computer time-sharing system receives teleport inquiries at an average rate of .1 per millisecond. Find the probab
Sphinxa [80]

Answer:  a) 0.9980, b) 0.0013, c) 0.0020, d) 0.00000026, e) 0.0318

Step-by-step explanation:

Problem 8-4 A computer time-sharing system receives teleport inquiries at an average rate of .1 per millisecond. Find the probabilities that the number of inquiries in a particular 50-millisecond stretch will be:

Since we have given that

\lambda=0.1\ per\ millisecond=5\ per\ 50\ millisecond=5

Using the poisson process, we get that

(a) less than or equal to 12

probability=  P(X\leq 12)=\sum _{k=0}^{12}\dfrac{e^{-5}(-5)^k}{k!}=0.9980

(b) equal to 13

probability= P(X=13)=\dfrac{e^{-5}(-5)^{13}}{13!}=0.0013

(c) greater than 12

probability= P(X>12)=\sum _{k=13}^{50}\dfrac{e^{-5}.(-5)^k}{k!}=0.0020

(d) equal to 20

probability= P(X=20)=\dfrac{e^{-5}(-5)^{20}}{20!}=0.00000026

(e) between 10 and 15, inclusively

probability=P(10\leq X\leq 15)=\sum _{k=10}^{15}\dfrac{e^{-5}(-5)^k}{k!}=0.0318

Hence, a) 0.9980, b) 0.0013, c) 0.0020, d) 0.00000026, e) 0.0318

6 0
3 years ago
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