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xz_007 [3.2K]
2 years ago
11

What is 3/4 inches of 15 ft

Mathematics
1 answer:
Fofino [41]2 years ago
6 0
So .. in 1foot, there are 12inches... thus, in 15feet, there are 15*12 inches

how many in 3/4 of an inch?  well  \bf \begin{array}{ccllll}
feet&inches\\
\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\
15&15\cdot 12\\
x&\frac{3}{4}
\end{array}\implies \cfrac{15}{x}=\cfrac{15\cdot 12}{\frac{3}{4}}\implies \cfrac{15}{x}=\cfrac{\frac{15\cdot 12}{1}}{\frac{3}{4}}
\\\\\\
\cfrac{15}{x}=\cfrac{15\cdot 12}{1}\cdot \cfrac{4}{3}\implies \cfrac{15}{x}=\cfrac{15\cdot 12\cdot 4}{3}

solve for "x"
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The sum of two positive integers, a and b, is at least 30. The difference of the two integers is at least 10. If b is th
Dafna11 [192]

Answer:

a + b \geq 30

b - a \geq 10

Step-by-step explanation:

Given

The sum of the two positive integer a and b is at least 30, this means the sum of the two positive integer is 30 or greater than 30, so we write the inequalities as below.

a + b \geq 30

The difference of the two integers is at least 10, if b is the greater integer then we subtract integer a from integer b, so we write the inequality as below.

b - a \geq 10

Therefore, the following system of inequalities could represent the values of two positive integers a and b.

a + b \geq 30

b - a \geq 10

6 0
3 years ago
How to solve this equation algebraically: Y=2x+1<br> 3x+4y=26
AURORKA [14]
You can substitute what y is into the second equation, so:
3x + 4(2x + 1) = 26
3x + 8x + 4 = 26
11x + 4 = 26
- 4
11x = 22
÷ 11
x = 2

y = (2 × 2) + 1
y = 5 + 1
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So you get x as 2 and y as 5, I hope this helps!
3 0
3 years ago
Evaluate the expression 2b to the third power+ 5 when b=5
Andrej [43]

Answer:

1005

Step-by-step explanation:

10 to the third power + 5 =

1000 + 5 =

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7 0
3 years ago
I need an answer!! (marking as brainliest)
irina1246 [14]

Answer: I hope this helps.

Step-by-step explanation:

5 0
10 months ago
A) how many ways are there to choose 10 players to take the field?
Kruka [31]

A. C(13, 10) = 13! = 13·12·11 = 13 · 2 · 11 = 286.C(13, 10) = 13! = 13·12·11 = 13 · 2 · 11 = 286.

B. P(13,10)= 13! =13! =13·12·11·10·9·8·7·6·5·4. (13−10)! 3!

C. f there is exactly one woman chosen, this is possible in C(10, 9)C(3, 1) =

10! 3!

9!1! 1!2! 10! 3!

8!2! 2!1! 10! 3!

7!3! 3!0!

= 10 · 3 = 30 ways; two women chosen — in C(10,8)C(3,2) =

= 45·3 = 135 ways; three women chosen — in C(10, 7)C(3, 3) =

= 10·9·8 ·1 = 120 ways. Altogether there are 30+135+120 = 285 1·2·3

<span>possible choices.</span><span> 
</span>

  


5 0
3 years ago
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