Answer:
P(Z < 2.37) = 0.9911.
Step-by-step explanation:
We are given that Let z denote a random variable that has a standard normal distribution.
Let Z = a random variable
So, Z ~ Standard Normal(0, 1)
As we know that the standard normal distribution has a mean of 0 and variance equal to 1.
Z =
~ N(0,1)
where,
= mean = 0
= standard deviation = 1
Now, the probability that z has a value less than 2.37 is given by = P(Z < 2.37)
P(Z < 2.37) = P(Z <
) = P(Z < 2.37) = 0.9911
The above probability is calculated by looking at the value of x = 2.37 in the z table which has an area of 0.9911.
Answer:
answer is attached on the photo
Factor by grouping.
(7x+2)(x-2) I think not sure
This is basically a simple problem to understand. The only thing that needs to be done is to divide the mass of the sun by the mass of mercury. It will give the required result.
Number of times the mass of sun is greater than
the mass of mercury = 21.3525×102921.3525×1029/<span>328.5×1021328.5×1021
= </span><span>7.1783629e+15
I hope that this is the answer that you were looking for and it has come to your great help.</span>