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sammy [17]
4 years ago
7

You may go through the testing stage of technological design several times before coming up with a suitable solution to a proble

m. True False
Chemistry
2 answers:
tensa zangetsu [6.8K]4 years ago
5 0
The answer to your question is false
OLga [1]4 years ago
4 0
Well it will obviously be false hope this helps ☺️
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Which determines the state of matter for any material?
kodGreya [7K]
By state of matter I assume you mean solid, liquid, gas, in which case the answer would be C.
the behaviour of molecules:
- in a solid is low energy with limited activity where molecules only vibrate, cannot mould to shape of container
- in a liquid is with moderate energy, with molecules flowing over the top of one another, and thus can mould to the shape of the container
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4 0
3 years ago
Determine the kinds of intermolecular forces that are present in each element or compound. you may want to reference ( pages 466
Alla [95]
<span>Majorly there are four types of inter molecular forces: Permanent dipole (like in HCl or NaCl) Ion dipole and Ion induced dipole Hydrogen bonding Van der Waals forces (Keesom, Debye, and London dispersion force)</span>
5 0
3 years ago
The role of sodium hydroxide in the synthesis of a chalcone is to
dalvyx [7]

Explanation:

Chemical formula of chalcone is C_{15}H_{12}O and during the preparation of chalcones, a base like sodium hydroxide acts like a catalyst. This catalyst helps in the abstraction of proton from the methyl group acetophenone in order to obtain a negative charge methylene group.

This methylene group then attacks carbonyl carbon of the benzaldehyde.

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3 years ago
Which equation expresses the solubility product of Zn3(PO4)2?
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Hope It Helps You ✌️

3 0
3 years ago
Consider the following reaction at 298.15 K: Co(s)+Fe2+(aq,1.47 M)⟶Co2+(aq,0.33 M)+Fe(s) If the standard reduction potential for
fgiga [73]

Answer:

The correct answer is 0.186 V

Explanation:

The two hemirreactions are:

Reduction: Fe²⁺ + 2 e- → Fe(s)  

Oxidation : Co(s)  → Co²⁺ + 2 e-

Thus, we calculate the standard cell potential (Eº) from the difference between the reduction potentials of cobalt and iron, respectively,  as follows:

Eº = Eº(Fe²⁺/Fe(s)) - Eº(Co²⁺/Co(s)) = -0.28 V - (-0.447 V) = 0.167 V

Then, we use the Nernst equation to calculate the cell potential (E) at 298.15 K:

E= Eº - (0.0592 V/n) x log Q

Where:

n: number of electrons that are transferred in the reaction. In this case, n= 2.

Q: ratio between the concentrations of products over reactants, calculated as follows:

Q = \frac{ [Co^{2+} ]}{[Fe^{2+} ]} = \frac{0.33 M}{1.47 M} = 0.2244

Finally, we introduce Eº= 0.167 V, n= 2, Q=0.2244, to obtain E:

E= 0.167 V - (0.0592 V/2) x log (0.2244) = 0.186 V

4 0
4 years ago
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