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Amiraneli [1.4K]
4 years ago
15

If 8 batteries cost $22 how many does 1 battery cost?

Chemistry
2 answers:
Strike441 [17]4 years ago
3 0
The answer is 2.75 because you divide 22 by 8
Anuta_ua [19.1K]4 years ago
3 0
The answer should be 2.72.
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How could you find the molar mass of a compound such as water (H2O)
NeTakaya
You can find it by adding the standard atomic masses of the constituent atoms.
5 0
4 years ago
How many moles of AgNO3 must react to form 0. 854 mol Ag? mol AgNO3.
babunello [35]

The moles of silver nitrate required to form 0.854 mol silver ion has been 0.854 mol.

The balanced chemical equation for the dissolution of silver nitrate has been:

\rm AgNO_3\;\rightarrow\;Ag^+\;+\;NO_3^-

The aqueous solution of silver nitrate has been dissociated into the constituent silver and nitrate ions.

In a balanced chemical equation, the coefficient has been equivalent to the moles of each reactant forming the moles of product.

From, the balanced equation,

\rm 1\;mol\;AgNO_3=1\;mol\;Ag

The given moles of Silver has been 0.854 mol. Thus, the moles of silver nitrate required has been given as:

\rm 1\;mol\;Ag^+=1\;mol\;AgNO_3\\0.854\;mol\;Ag^+=0.854\;\times\;1\;mol\;AgNO_3\\0.854\;mol\;Ag^+=0.854\;mol\;AgNO_3

The moles of silver nitrate required to form 0.854 mol silver ion has been 0.854 mol.

For more information about the moles produced, refer to the link:

brainly.com/question/10606802

6 0
2 years ago
3. Which part of Thomson's plum pudding model was different from Rutherford's model?
horsena [70]

Answer:

The difference between the Thompson's plum pudding model and the Rutherford atom model is the location of the electrons (option a).

Explanation:

While Thompson compared his atom to a plum pudding, where the electrons floated freely in the pudding, Rutherford established the arrangement of the electrons in orbitals, which were found around the atomic nucleus like the planets around the sun.

Rutherford's findings also established the existence of a small, positively charged nucleus.

<em>Thompson and Rutherford models did not differentiate between the charges of electrons and protons , overall charges or overall size of the atom.</em>

8 0
3 years ago
For the following reaction, 5.22 grams of aluminum oxide are mixed with excess sulfuric acid. The reaction yields 12.9 grams of
Mamont248 [21]

Answer:

m_{Al_2(SO_4)_3}=17.5gAl_2(SO_4)_3

Explanation:

Hello,

In this case, the undergoing balanced chemical reaction is:

Al_2O_3(s)+3H_2SO_4(aq)\rightarrow Al_2(SO_4)_3(aq)+3H_2O(l)

Thus, as 5.22 grams of aluminium oxide reacts, the required yielded amount of aluminium sulfate results:

m_{Al_2(SO_4)_3}=5.22gAl_2O_3*\frac{1molAl_2O_3}{102gAl_2O_3}*\frac{1molAl_2(SO_4)_3}{1molAl_2O_3}*\frac{342gAl_2(SO_4)_3}{1molAl_2(SO_4)_3} \\\\m_{Al_2(SO_4)_3}=17.5gAl_2(SO_4)_3

Moreover, the percent yield is:

Y=\frac{12.9g}{17.5g} *100\%=73.7\%

Best regards.

6 0
4 years ago
For each of the following pairs of solutes and solvent, predict whether the solute would be soluble or insoluble. After making y
kakasveta [241]

Answer and Explanation

The major rule of Solubility is that, 'like dissolves like', that is, polar solutes dissolve in polar solvents and non-polar solute dissolve in non-polar solvents. Polar solutes will not dissolve in non-polar solvents & vice-versa.

a) Malic Acid in Water - Soluble

Malic Acid, C₄H₆O₅, has a solubility of 558g/L in water at 25°C.

558 g/L = 558 mg/mL >> 40 mg/mL. This indicates that Malic Acid is very soluble in water.

Malic Acid is a dicarboxylic acid, therefore, it is a polar compound which is expected to be soluble in water as short chained polar organic compounds like itself are soluble in water.

b) Naphtalene in Water - Insoluble

Naphtalene, C₁₀H₈ has a solubility of 31.6 mg/L In water at 25°C.

31.6 mg/L = 0.0316 mg/mL <<< 40 mg/mL. This indicates that Naphtalene is very insoluble in water.

The insolubility of Naphtalene can be explained by the very non-polar nature of the organic compound.

c) Amphetamine in ethyl alcohol - Insoluble

Amphetamine, C₉H₁₃N has a solubility of 0.0165 g/mL in ethyl alcohol at 25°C.

0.0165 g/mL = 1.65 mg/mL << 40mg/mL

Amphetamine contains one benzene ring and one amine group. Even though, amine group makes the compound polar, the benzene ring and hydrocarbon chain overwhelm the polarity and cause amphetamine to be non-polar. Ethyl alcohol is polar due to having an alcohol functional group. By applying ‘Like dissolve like’, amphetamine is insoluble in ethyl alcohol.

d) Aspirin in water - Insoluble

Aspirin, C₉H₈O₄ has a solubility of 3mg/mL in water at 25°C.

3mg/mL << 40 mg/mL.

Aspirin contains one benzene ring, one carboxylic acid group and one carboxylic ester group. Even though, the carboxylic acid group and carboxylic ester group are polar, the benzene ring dominate and make aspirin nonpolar. Water is polar. By using ‘Like dissolve like’ rule, aspirin is insoluble in water.

e) Succinic acid in hexane - Insoluble.

Succinic acid, C₄H₆O₄ is insoluble in hexane.

Succinic acid contains two carboxylic acid groups which make the compound polar. However, hexane is nonpolar due to a long chain of hydrocarbon. By using ‘Like dissolve like’ rule, succinic acid is insoluble in hexane.

f) Ibuprofen in diethyl ether - Insoluble

Ibuprofen is insoluble in diethyl ether.

Ibuprofen contalns a complex chain of hydrocarbons with a benzene ring in between the chain and a carboxylic acid group. However, the big chain of hydrocarbons dominates the polarity

of the compound and makes it non-polar. Similarly, diethyl ether is a non-palar compound due the having an other group. By using 'Like dissolve like' rule, ibuprofen is soluble in diethyl ether since they are both nonpolar.

g) 1-Decanol (n-deryl alcohol) in water - slightly soluble.

1-decanol has a solubility of 37mg/L in water at 20°C.

37mg/L = 0.037 mg/mL << 40 mg/mL (Insoluble).

1-decanol is an alcohol. However, 1-decanol is a slightly polar compound since it has a 10-carbon chain and a hydroxyl group. Water is polar. So, because of this, 1-decanol is not so soluble in water.

3 0
4 years ago
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