Answer:
how many liters of 0.150 m hcl would be required to react completely with 8.00 grams of magnesium hydroxide
Explanation:
please give me brainlist and follow
The balanced redox equation of the reaction is given below:
- I⁻ + 2 MnO₄ + H₂O → IO₃⁻ + 2 MnO₂ + 2 OH⁻
The oxidizing agent is MnO₄ while the reducing agent is I⁻.
<h3>What are redox equations?</h3>
Redox equations are equations in which oxidation and reduction reactions occur together.
Redox reactions can take place in alkaline or acidic mediums.
The balanced redox equation of the reaction is given below:
- I⁻ + 2 MnO₄ + H₂O → IO₃⁻ + 2 MnO₂ + 2 OH⁻
The oxidizing agent is MnO₄ while the reducing agent is I⁻
In conclusion, a balanced redox equation is one in which the atoms and the change in oxidation state is equal on both sides of the reaction.
Learn more about redox equations at: brainly.com/question/27239694
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Most likely true..it's a food chain.
everone is hungry and depending on some type of food..and if they can't get it and eat it, eventually they die
Answer:
See explanation
Explanation:
From the analysis we have in the question, we must look towards a first row transition metal ion having a d^6 configuration because it yields a paramagnetic complex having four unpaired electrons and a diamagnetic complex having no unpaired electrons.
We have two possible candidates in mind, Fe^2+ and Co^3+. However, Fe^2+ does not form as many coloured complexes as stated in the question so we have to eliminate that option.
We are now left with only Co^3+. Various ligands are going to cause these various colours of Co^3+ to appear in solution.
Hence, we can deduce from all these that the nature of ligands determines the colour of the complex . Don't forget that the colour of a complex arises from crystal field splitting.
The Property of A Double Displacement Reaction is that the Element in front of a compound displaces the Other Metal in front of the other Compound. For eg.
BaCl2+Na2SO4=BaSO4+2NaCl
Here Barium, the metal in front of the compound BaCl2 displaces Na, the metal in front of the compound Na2SO4 to form BaSO4 and NaCl.