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Ksju [112]
3 years ago
12

The role of sodium hydroxide in the synthesis of a chalcone is to

Chemistry
1 answer:
dalvyx [7]3 years ago
5 0

Explanation:

Chemical formula of chalcone is C_{15}H_{12}O and during the preparation of chalcones, a base like sodium hydroxide acts like a catalyst. This catalyst helps in the abstraction of proton from the methyl group acetophenone in order to obtain a negative charge methylene group.

This methylene group then attacks carbonyl carbon of the benzaldehyde.

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Given the balanced equation representing a reaction at 101.3 kPa and 298 K:
ser-zykov [4K]
Answer (4)

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the change of enthalpy (ΔH) is greater <span>than zero.
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8 0
3 years ago
A gas evolved during the fermentation of alcohol had a volume of 19.4 L at 17 °C and 746 mmHg. How many moles of gas were collec
AlexFokin [52]

Answer:- 0.800 moles of the gas were collected.

Solution:- Volume, temperature and pressure is given for the gas and asks to calculate the moles of the gas.

It is an ideal gas law based problem. Ideal gas law equation is used to solve this. The equation is:

PV=nRT

Since it asks to calculate the moles that is n, so let's rearrange this for n:

n=\frac{PV}{RT}

V = 19.4 L

T = 17 + 273 = 290 K

P = 746 mmHg

we need to convert the pressure from mmHg to atm and for this we divide by 760 since, 1 atm = 760 mmHg

P=746mmHg(\frac{1atm}{760mmHg})

P = 0.982 atm

R = 0.0821\frac{atm.L}{mol.K}

Let's plug in the values in the equation to get the moles.

n=\frac{0.982atm*19.4L}{0.0821\frac{atm.L}{mol.K}*290K}

n = 0.800 moles

So, 0.800 moles of the gas were collected.

4 0
3 years ago
What is the starting molecule for glycolysis?
meriva
Glucose is the starting molecule for glycolysis.
5 0
3 years ago
The temperature of a city during a week was 35° C, 36°C, 34°C, 38°C, 40°C, 39°C and 44°C. What was the average daily temperature
Zigmanuir [339]

Answer:38°

Explanation:

8 0
3 years ago
If 10.57 g of magnesium reacts completely with 6.96 g of oxygen, what is the percent by mass of oxygen in magnesium oxide? Round
Deffense [45]

Answer:

39.7 %

Explanation:

magnesium + oxygen ⟶ magnesium oxide

   10.57 g         6.96 g               17.53 g

According to the <em>Law of Conservation of Mass</em>, the mass of the product must equal the total mass of the reactants.

Mass of MgO = 10.57 + 6.96

Mass of MgO = 17.53 g

The formula for mass percent is

% by mass = Mass of component/Total mass × 100 %

In this case,

% O = mass of O/mass of MgO × 100 %

Mass of O = 6.96 g

Mass of MgO = 17.53 g

% O = 6.96/17.53 × 100

% O = 0.3970 × 100

% O = 39.7 %

5 0
3 years ago
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