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3 years ago

Very confusing problem

Mathematics

1 answer:

Ronch [10]3 years ago

4 0

Answer:

b = 5

Step-by-step explanation:

if parallelogram is a rectangle, then the two diagonals has the same length

10/12 x(24/5 x b - 36/5) = 2/3 x (3b + 6)

4b - 6 = 2b + 4

2b = 10

b = 5

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Write an equation of the line that passes through the point (1,3) and has a slope of -2

jek_recluse [69]

Answer:

y= -2x+1

Step-by-step explanation:

y=mx+b

y= -2x +b

3= -2(1) +b

3= -2 +b

b=1

y= -2x+1

4 0

2 years ago

The square root of 80

pochemuha

Sqrt(80) = Sqrt(16) x sqrt(5)
= 4 x sqrt(5)

6 0

3 years ago

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Elenna [48]

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8 0

2 years ago

Given r(x) = startfraction 11 over (x minus 4) squared endfraction , which represents a domain restriction on r(x) and the corre

Dmitry_Shevchenko [17]

The domain and inverse of the function

$r(x) = \frac{11}{(x - 4)^2}$ is

Domain = $\mathbb{R} - \{4\}$ ,

$r^{-1}(x) = \pm \sqrt{\frac{11}{x}} + 4$

What is a function?

A function from A to B is a rule that assigns to each element of A a unique element of B. A is called the domain of the function and B is called the codomain of the function.

There are different operations on functions like addition, subtraction, multiplication, division and composition of functions.

The given function is

$r(x) = \frac{11}{(x - 4)^2}$

r(x) is not defined if x - 4 = 0

r(x) is not defined for x = 4

Domain = $\mathbb{R} - \{4\}$ ,

Where $\mathbb{R}$ is the set of all real number

Let r(x) = y

$\frac{11}{(x-4)^2} = y\\(x - 4)^2 = \frac{11}{y}\\x - 4 = \pm \sqrt{\frac{11}{y}}\\x = \pm\sqrt{\frac{11}{y}} +4$

$r^{-1}(x) = \pm \sqrt{\frac{11}{x}} + 4$

To learn more about function, refer to the link:

brainly.com/question/22340031

#SPJ4

3 0

1 year ago

Compare rates of change.

MrMuchimi

Y=foot
x=foram

A. easy, plug 17 for x and evaluage for y
y=0.860(17)+3.302
y=14.62+3.302
y=17.922 inches

B. rate of change is slope
y=mx+b
m=slope
so
rate or change is 0.860 inches per legnth of forarm

C. what data

D. it is a function
since it is 1st degree (no exponents greater than 1 on the placeholder), and it is not a vertical line
it is a function

7 0

3 years ago