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Lynna [10]
4 years ago
12

Very confusing problem

Mathematics
1 answer:
Ronch [10]4 years ago
4 0

Answer:

b = 5

Step-by-step explanation:

if parallelogram is a rectangle, then the two diagonals has the same length

10/12 x(24/5 x b - 36/5) = 2/3 x (3b + 6)

4b - 6 = 2b + 4

2b = 10

b = 5

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N2-14n+49 what’s the answer
stira [4]
(n-7) (n-7) will be your answer

n x n = n²

n x -7 = -7n
n x - 7 = -7n
-7n +(-7n) = -14n
-7 x -7 = 49

(n-7)²  is your answer

hope this helps

and if you are doing the other thing

n = 7, 7

hope this helps
5 0
3 years ago
Read 2 more answers
Will give crown thanks
Tatiana [17]

Answer:

A is right

B is acute

C is obtuse

D is right

Step-by-step explanation:

90 is right

anything under 90 is acute

over 90 obtuse

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3 years ago
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8.025 x 10*-8 in standard form
ira [324]

Answer:  

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Step-by-step explanation:

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3 years ago
Almost all medical schools require applicants to take the Medical College Admission Test (MCAT). To estimate the mean score of t
jenyasd209 [6]

Answer:

97.92% probability that the mean score of your sample is between 22 and 28

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 25, \sigma = 6.5, n = 25, s = \frac{6.5}{\sqrt{25}} = 1.3

What is the probability that the mean score of your sample is between 22 and 28

This is the pvalue of Z when X = 28 subtracted by the pvalue of Z when X = 22. So

X = 28

Z = \frac{X - \mu}{\sigma}

By the Central Limit theorem

Z = \frac{X - \mu}{s}

Z = \frac{28 - 25}{1.3}

Z = 2.31

Z = 2.31 has a pvalue of 0.9896

X = 22

Z = \frac{X - \mu}{s}

Z = \frac{22 - 25}{1.3}

Z = -2.31

Z = -2.31 has a pvalue of 0.0104

0.9896 - 0.0104 = 0.9792

97.92% probability that the mean score of your sample is between 22 and 28

8 0
3 years ago
Please help due tonight !
faust18 [17]
The equation: 6r-3=45
6r=48
Answer: r=8
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3 years ago
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