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Akimi4 [234]
3 years ago
10

I need help please help me!!

Mathematics
2 answers:
galben [10]3 years ago
4 0
I wish I could help you man but I suck with math
mezya [45]3 years ago
4 0
While I'm not entirely sure what this question is expecting of you, I can help.
A={4,7,10,13,17} B={3,5,7,9}

If you were to find the union, it would be: {3,4,5,7,9,10,13,17}
If you wanted to find where these two INTERSECT, then it would definitely be 7

It looks to me, if that is what your first choice is saying, that it's the first option: A U B=7. But I am unfamiliar with some of these terms, so if this ISN'T what option A is saying, then don't go with it.

But from my knowledge, it looks like the first choice is correct. 

~Hope this helps m8
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Which ordered pairs lie on the graph of the exponential function f(x)=-3(x-1)+2
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Step-by-step explanation:

Hope this helps!!

4 0
2 years ago
Simplify the linear expression.
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Step-by-step explanation:I took the K12 test I hope this helps.

4 0
2 years ago
Expand the equation (p+q)^5
VashaNatasha [74]
(p + q)⁵
(p + q)(p + q)(p + q)(p + q)(p + q)
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(p² + pq + pq + q²)(p² + pq + pq + q²)(p + q)
(p² + 2pq + q²)(p² + 2pq + q²)(p + q)
{[p²(p² + 2pq + q²) + 2pq(p² + 2pq + q²) + q²(p² + 2pq + q²)](p + q)}
{[p²(p²) + p²(2pq) + p²(q²) + 2pq(p²) + 2pq(2pq) + 2pq(q²) + q²(p²) + q²(2pq) + q²(q²)](p + q)}
(p⁴ + 2p³q + p²q² + 2p³q + 4p²q² + 2pq³ + p²q² + 2pq³ + q⁴)(p + q)
(p⁴ + 2p³q + 2p³q + p²q² + 4p²q² + p²q² + 2pq³ + 2pq³ + q⁴)(p + q)
(p⁴ + 4p³q + 6p²q² + 4pq³ + q⁴)(p + q)
p⁴(p + q) + 4p³q(p + q) + 6p²q²(p + q) + 4pq³(p + q) + q⁴(p + q)
p⁴(p)+ p⁴(q) + 4p³q(p) + 4p³q(q) + 6p²q²(p) + 6p²q²(q) + 4pq³(p) + 4pq³(q) + q⁴(p) + q⁴(q)
p⁵ + p⁴q + 4p⁴q + 4p³q² + 6p³q² + 6p²q³ + 4p²q³ + 4pq⁴ + pq⁴ + q⁵
p⁵ + 5p⁴q + 10p³q² + 10p²q³ + 5pq⁴ + q⁵
7 0
3 years ago
(2 x 10) + (9 x 1) + (7 x 1/10) + (8x 1/1000) in standard form
Pepsi [2]

Answer:The number is 209.708

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
PART A. Expand the polynomial (x2 − y2)2 + (2xy)2, then simplify it by combining like terms.
sweet-ann [11.9K]
(x2-y1)²+(2xy)1 =
x⁴-2x²y²+y⁴+4x²y² =
x⁴+2x²y²+y⁴=
(x²+y²)²
4 0
3 years ago
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