Answer:
We can easily find out the beginning point of the line by using dot representation.
When it comes to position vector, it expresses the exact position of certain object from the starting point of the coordinate system.
The vector is a straight line that has a certain end which is fixed to its body.
The other end is linked with a moving point that tells an accurate position of that specific point.
Answer:
Noble gases because they have a full outer shell of electrons.
Explanation:
Noble gases usually called inert gases are generally non reactive gases. They belong to group 18 elements.They tend to not gain the electron or not give up a electron as they have full valence shells. Because they already have full valence shell and therefore full outer energy level, they are very stable and hardly react with any other elements.
Answer: You do not specify what is being asked for. ∆E? ∆H?
∆E = (430 - 238) J = 192 J
∆H = 430 J
Explanation:
If asked for the value of ∆H the answer is simply the change in heat, and in the question, it states introduction of 430 J of heat is causing the system to expand.
Therefore ∆H = 430 J
If asked for ∆E, we know that ∆E = ±q (heat) + work (-P∆V) = ±q + w
The question states that 238 J of work are done AND the system expanded
(work is negative because expansion means work is done BY the system, releasing energy/heat... Conversely, if the system were compressed, work is done ON the system, absorbing heat/energy)
Therefore, ∆E = (430 - 238) J = 192 J
Answer:
t = √ 2y₀ / g
if they are at the same height, all the bullets must carry the target, since when advancing the height decreases
Explanation:
In this exercise we see that the bullets are fired horizontally so the time it takes to reach the ground is
y = y₀ + t - ½ g t²
as they are fired horizontally their vertical velocity is zero and the height upon reaching the ground is zero y = 0
0 = y₀ - ½ g t²
t = √ 2y₀ / g
from here we can see that the time it takes for the bullets to hit the floor depends only on the initial height
Therefore, all the bullets that come out of the same height reach the ground at the same time, but at a different distance, so if one misses the target, everything must fail since reaching the target is below the initial height.
The horizontal distance traveled by the bullets is
x = v₀ₓ t
v₀ₓ =v₀
x = v₀ √2y₀/g
For a more precise calculation we should know the height of the target and the bullets, but if they are at the same height, all the bullets must carry the target, since when advancing the height decreases