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2 years ago

What value of x is in the solution set of 2(3x – 1) ≥ 4x – 6?

1 answer:

4 0

2(3x - 1) ≥ 4x - 6 Remove the brackets on the left.
6x - 2 ≥ 4x - 6 Subtract 4x from both sides.
6x - 4x - 2 ≥ - 6 combine like terms on the left.
2x - 2 ≥ - 6 Add 2 to both sides
2x ≥ - 6+ 2
2x ≥ -4 Divide by 2
x ≥ - 4/2
x ≥ - 2 answer <<<<<<<<

Check
2(3*-2 - 1) ≥ 4x - 6
2(-6 - 1) ≥ 4(-2) - 6
2(-7) ≥- 8 - 6
- 14 = - 14 and this checks.

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A mass of 148 g stretches a spring 13 cm. The mass is set in motion from its equlibrium position with a downward velocity of 10

Charra [1.4K]

Answer:

$u(t)=1.15 \sin (8.68t)cm$

0.3619sec

Explanation:

Given that

Mass,m=148 g

Length,L=13 cm

Velocity,u'(0)=10 cm/s

We have to find the position u of the mass at any time t

We know that

$\omega_0=\sqrt{\frac{g}{L}}\\\\=\sqrt{\frac{980}{13}}\\\\=8.68 rad/s$

Where $g=980 cm/s^2$

$u(t)=Acos8.68 t+Bsin 8.68t$

u(0)=0

Substitute the value

$A=0\\u'(t)=-8.68Asin8.68t+8.68 Bcos8.86 t$

Substitute u'(0)=10

$8.68B=10$

$B=\frac{10}{8.68}=1.15$

Substitute the values

$u(t)=1.15 \sin (8.68t)cm$

Period =T = 2π/8.68

After half period

π/8.68 it returns to equilibruim

π/8.68 = 0.3619sec

6 0

3 years ago

What is conflict resolution?

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Conflict resolution is conceptualized as the methods and processes involved in facilitating the peaceful ending of conflict and retribution.

7 0

2 years ago

In your own words explain efficiency

Oliga [24]

Efficiency is completing a task as fast a possible the the least amount of effort.

7 0

2 years ago

Read 2 more answers

Pls help in these 2 questions

Nadya [2.5K]

Answer:

Taking forces along the plane

F cos θ - M g sin θ -100 = M a net of forces along the plane

F = (M a + M g * .5 + 100) / .866 solving for F

F = (80 * 1.5 + 80 * 9.8 * .5 + 100) / .866 = 707 N

F = 707 N acting along the plane

Fn = F sin θ + M g cos θ forces acting perpendicular to plane

Fn = 707 * 1/2 + 80 * 9.8 * .866 = 1030 Newtons forces normal to plane

(this would give a coefficient of friction of 100 / 1030 = .097 = Fn)

4 0

2 years ago

11) A sled is initially given a shove up a frictionless 35º incline. It reaches a maximum height of 2.5

Andrej [43]

Answer:

7 m/s

Explanation:

To solve this problem you must use the conservation of energy.

$K1 +U1=K2+U2$

That math speak for, initial kinetic energy plus initial potential energy equals final kinetic energy plus final potential energy.

The initial PE (potential energy) is 0 because it hasn't been raised in the air yet. The final KE (kinetic energy) is 0 because it isn't moving. This gives the following:

$KE1= \frac{1}{2}mv^{2}}$

$PE2=mgh$

K1=U2

$\frac{1}{2} mv^{2} =mgh$

Solve for v

$v=\sqrt{2gh}$

Input known values and you get 7 m/s.

5 0

2 years ago