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2 years ago

14

What value of x is in the solution set of 2(3x – 1) ≥ 4x – 6?

1 answer:

Akimi4 [234]2 years ago

4 0

2(3x - 1) ≥ 4x - 6 Remove the brackets on the left.
6x - 2 ≥ 4x - 6 Subtract 4x from both sides.
6x - 4x - 2 ≥ - 6 combine like terms on the left.
2x - 2 ≥ - 6 Add 2 to both sides
2x ≥ - 6+ 2
2x ≥ -4 Divide by 2
x ≥ - 4/2
x ≥ - 2 answer <<<<<<<<

Check
2(3*-2 - 1) ≥ 4x - 6
2(-6 - 1) ≥ 4(-2) - 6
2(-7) ≥- 8 - 6
- 14 = - 14 and this checks.

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maw [93]

F= Force
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3 years ago

an object weighting 100g is thrown upwards from the ground at a speed of 100 m/s.where will the potential energy of the object b

Kay [80]

Answer:

333.3 m

Explanation:

Given

$m =100g\ =\ 0.1kg\\v = 100 m/s\\g = 10 m/s ^2$

Potential energy = $\frac{2}{3}\ of\ Kinetic\ energy$ ......Equation(1)

We know that

Potential energy=mgh

Kinetic energy = $\frac{1}{2} mv^{2}$

Now From the Equation(1)

$mgh=\frac{2}{3}*\frac{1}{2} mv^{2}\\ gh=\frac{v^{2} }{3} \\10 * h=\ \frac{10000}{3}\\ h=\ \frac{1000}{3} \\h=333.3\ m$

3 0

2 years ago

The area of the piston to the master cylinder in a hydraulic braking system of a car is 0.6 square inches. If a force of 5.6 lb

balu736 [363]

Answer:

16.8 lb is the force on the brake pad of one wheel.

Explanation:

Force applied on the piston = $F_1=5.6 lb$

Area of the piston = $A_1=0.6 inches^2$

Force applied on the brakes = $F_2$

Area of the brakes = $A_2=1.8 inches^2$

Applying Pascal's law: 'For an incompressible fluid pressure at one surface is equal to the pressure at other surface'.

$\frac{F_1}{A_2}=\frac{F_2}{A_2}$

$F_2=\frac{5.6 lb\times 1.8 inhes^2}{0.6 inches^2}=16.8 lb$

16.8 lb is the force on the brake pad of one wheel.

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3 years ago

Given a die, would it be more likely to get a single 6 in six rolls, at least two 6s in twelve rolls, or at least one-hundred 6s

vichka [17]

Answer:

Explanation:

In first case we are interested in one time 6 in six rolls

Thus probability = number of chances required/Total chances

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Similarly in the second case probability = 2/12 = 1/6

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The probability is the same . Thus all the cases has equal chances

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3 years ago

A total of 750 j of work was done when a force of 125 n was exerted on a box to move it. how far was the box moved?

Slav-nsk [51]

Work = Force times Distance
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Given W = 750J, F = 125N;

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3 years ago