Answer: First find the GCF ( greatest Common Factor):-
GCF of 16, 24 and 48 is 8
GCF of the x terms is x^3
GCF of the y terms is y^4
So GCF is 8x^3y^4
Factoring:-
= 8x^3y^4 ( 2x^6y^4 - 16x^2y^2 + 3) answer
Step-by-step explanation:
Send me a photo and ill solve it because you gave me nothing to work with lol
<u>Answer with explanation:</u>
As per given , we have
A sample of 50 gribbles finds an average length of 3.1 mm with a standard deviation of 0.72.
i.e. n= 50
Degree of freedom = n-1=49


The point estimate of the population mean is equals to the sample mean.
i.e. The best estimate for the length of gribbles= 3.1 mm
Also, population standard deviation is unknown , then the confidence interval would be :

For df= 49 and significance level of 0.05 , the t- value (using t-distribution table) would be :

Now, Margin of error : 

95% confidence interval : 

Answer:
Step-by-step explanation:
It when you do this tan that equals 4:12
Answer:
4
Step-by-step explanation: