I think salt is it
........................
The difference is found in the DNA chromosome of the male and females.
The males have XY chromosomes at the last while the females have XX, these chromosome labels are important to signify deviancy and disparities among the morphology and the later structure of the female and male functions.
You’re answer is C. I hope this helps!
Answer:
A. Glucose:
As lactose is absent will follow the glucose metabolism, so the lac repressor will hold tightly with the operator which leads to the prevention of transcription as RNA polymerase can not bind to promoter so no lactose metabolism.
B. lactose:
In the case or wild mutant lactose metabolism will occur as lactose is present, allolactose binds to the lac repressor thus the operator and promoter are free so transcription starts. The same result will be in all test except in the case of a mutant repressor.
C. glucose and lactose:
In this case, diauxic growth will occur. This growth takes place when two sugars are present in the media. The preferred sugar will be consumed first That is glucose. Then a lag phase will come which will be followed by the second sugar metabolism that is lactose. the given two cases :
Lactose will be metabolized first, as operator site mutation prevents repressor protein binding and thus will lead to the constitutive synthesis of lac operon in test B.
The same thing will happen, as in this case also, constitutive synthesis of lac operon will happen in test C.
Cultures grown in the presence of both glucose and lactose are metabolizing lactose. In the test (b) and (c) will be responsible due to constitutive synthesis of lac operon will happen.
If the solution becomes transparent we could assume that ; The solution was hypotonic and the cells had burst.
<h3>Tonicity of red blood cells </h3>
To test for Tonicity of red blood cells, we placed the cells in a solution.When red blood cells are placed in hypotonic solution there is high rate of osmosis in which the solvent flows into the red cells placed in the solution the cells will experience a process known as Hemolysis and these cells do not diffuse light, the solution becomes a red transparent solution.
Hence we can conclude that If the solution becomes transparent we could assume that ; The solution was hypotonic and the cells had burst.
Learn more about Tonicity of red blood cells : brainly.com/question/6658551
