Ask question

Ask question

All categories

3 years ago

8

What dimensions of the box are required to fit the candle? 5 by 6 by 18 7 by 6 by 18 5 by 3 by 18 7 by 3 by 18

1 answer:

LiRa [457]3 years ago

4 0

The minimum height of the box must be 18 units, which is present in all the choices.
Another minimum dimension that we already know is 7 units, since it is an oblique box, and the projection of bottom-left to top-right is shown as 7 units.
That leaves us with the second (7x6) or fourth choice (7x3).

We have not been given the other dimension of the triangle, but from common sense, it looks longer than the front (5 units) leg, therefore 6 units is not an unreasonable dimension.

With 99.5% certainty, I would choose the second choice (7x6x18) because the remaining dimension does not look like 3 units long.

You might be interested in

Which grouping can be used to represent the product of 3x9?

Molodets [167]

Wouldn't you just multiply this, which is 3x9 = 27

6 0

2 years ago

Read 2 more answers

Paola's grandparents started a savings account for

pishuonlain [190]

Answer:

500

Step-by-step explanation:

ikw na mag explain nyan

4 0

3 years ago

A quality control engineer is interested in estimating the proportion of defective items coming off a production line. In a samp

fenix001 [56]

Answer:

The lower bound of a 99% C.I for the proportion of defectives = 0.422

Step-by-step explanation:

From the given information:

The point estimate = sample proportion $\hat p$

$\hat p = \dfrac{x}{n}$

$\hat p = \dfrac{55}{100}$

$\hat p$ = 0.55

At Confidence interval of 99%, the level of significance = 1 - 0.99

= 0.01

$Z_{\alpha/2} =Z_{0.01/2} \\ \\ = Z_{0.005} = 2.576$

Then the margin of error $E = Z_{\alpha/2} \times \sqrt{\dfrac{\hat p(1-\hat p)}{n}}$

$E = 2.576 \times \sqrt{\dfrac{0.55(1-0.55)}{100}}$

$E = 2.576 \times \sqrt{\dfrac{0.2475}{100}}$

$E = 2.576 \times0.04975$

E = 0.128156

E ≅ 0.128

At 99% C.I for the population proportion p is: $\hat p - E$

= 0.55 - 0.128

= 0.422

Thus, the lower bound of a 99% C.I for the proportion of defectives = 0.422

6 0

2 years ago

What are the answers to the last two questions?

ivanzaharov [21]

The answer to 15 is addition and multiplication

the answer to 16 is 0

8 0

3 years ago

During a tunnel construction project, engineers used explosives to excavate partway into a mountain. Because of time constraints

AnnyKZ [126]

The given data can be tabulated as:

number of days,x length of tunnel (ft), y

0 225

5 350

20 725

30 975

55 1,600

To check if the growth is linear, the slope at points (0, 225) and (5, 350), and (0, 225) and (20, 725) should be equal. The formula for slope is:

m = (y2 – y1) / (x2 – x1)

Finding for slope (0, 225) and (5, 350):

m = (350 – 225) / (5 – 0) = 25

Finding for slope (0, 225) and (20, 725):

m = (725 – 225) / (20 – 0) = 25

Therefore the equation is linear in the form of:

y = mx + b

where b is the value of y at x = 0, so b = 225

The complete equation is:

y = 25x + 225

At x = 86 days

y = 25(86) + 225

y = 2,375 ft

Therefore the length of the completed tunnel is 2,375 feet.

5 0

3 years ago