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Gnom [1K]
3 years ago
14

Solve the following equation 3(2x+7)=9

Mathematics
1 answer:
Anastasy [175]3 years ago
8 0
3(2x + 7) = 9 ...divide both sides by 3
2x + 7 = 9/3
2x + 7 = 3
2x = 3 - 7
2x = -4
x = -4/2
x = -2

or this way..
3(2x + 7) = 9
6x + 21 = 9
6x = 9 - 21
6x = - 12
x = -12/6
x = -2
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Write an equation for the nth term of the arithmetic sequence.<br> 17, 12, 7, 2, ...<br> an=
Lorico [155]

Answer:

An equation for the nth term of the arithmetic sequence 17, 12, 7, 2 is 17-5n.

Step-by-step explanation:

Given,

first term(a)=17

common difference (d)=t2-t1

=12-17

=-5

nth term of the arithmetic sequence = a+n×d

=17+n×-5

=17-5n

5 0
3 years ago
You work for a consumer advocate agency and want to find the mean repair cost of a washing machine. As part of your study, you r
Alenkasestr [34]

Answer:

90% confidence interval for the population mean is between a lower limit of $92.18 and an upper limit of $107.82.

Step-by-step explanation:

Confidence interval for a population mean is given as mean +/- margin of error (E)

mean = $100

sd = $25.20

n = 30

degree of freedom = n-1 = 30-1 = 29

confidence level (C) = 90% = 0.9

significance level = 1 - C = 1 - 0.9 = 0.1 = 10%

critical value (t) corresponding to 29 degrees of freedom and 10% significance level is 1.699

E = t×sd/√n = 1.699×25.20/√30 = $7.82

Lower limit of population mean = mean - E = 100 - 7.82 = $92.18

Upper limit of population mean = mean + E = 100 + 7.82 = $107.82

90% confidence interval is ($92.18, $107.82)

6 0
3 years ago
Read 2 more answers
A playground is being designed where children can interact with their friends in certain combinations. If there is 1 child, ther
mariarad [96]
<h2>Answer:</h2>

<em><u>Recursive equation for the pattern followed is given by,</u></em>

a_{n}=a_{n-1}+(n-1)^{2}

<h2>Step-by-step explanation:</h2>

In the question,

The number of interaction for 1 child = 0

Number of interactions for 2 children = 1

Number of interactions for 3 children = 5

Number of interaction for 4 children = 14

So,

We need to find out the pattern for the recursive equation for the given conditions.

So,

We see that,

a_{1}=0\\a_{2}=1\\a_{3}=5\\a_{4}=14\\

Therefore, on checking, we observe that,

a_{n}=a_{n-1}+(n-1)^{2}

On checking the equation at the given values of 'n' of, 1, 2, 3 and 4.

<u>At, </u>

<u>n = 1</u>

a_{n}=a_{n-1}+(n-1)^{2}\\a_{1}=a_{1-1}+(1-1)^{2}\\a_{1}=0+0=0\\a_{1}=0

which is true.

<u>At, </u>

<u>n = 2</u>

a_{n}=a_{n-1}+(n-1)^{2}\\a_{2}=a_{2-1}+(2-1)^{2}\\a_{2}=a_{1}+1\\a_{2}=1

Which is also true.

<u>At, </u>

<u>n = 3</u>

a_{n}=a_{n-1}+(n-1)^{2}\\a_{3}=a_{3-1}+(3-1)^{2}\\a_{3}=a_{2}+4\\a_{3}=5

Which is true.

<u>At, </u>

<u>n = 4</u>

a_{n}=a_{n-1}+(n-1)^{2}\\a_{4}=a_{4-1}+(4-1)^{2}\\a_{4}=a_{3}+9\\a_{4}=14

This is also true at the given value of 'n'.

<em><u>Therefore, the recursive equation for the pattern followed is given by,</u></em>

a_{n}=a_{n-1}+(n-1)^{2}

3 0
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kolbaska11 [484]
100% of Kerion's paper squares are:
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 answer
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