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sladkih [1.3K]
3 years ago
7

What is 7.358 rounded to the hundredths place

Mathematics
1 answer:
Ostrovityanka [42]3 years ago
4 0

Answer:

7.36

The drawing will help

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abruzzese [7]
Find 10% of it (just move the decimal point one spot to the left) and multiply by 4
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3 years ago
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Solve the system of equations: {2(3x-2y)+1=7x, 12(x+y)-15=7x+12y
fgiga [73]

Step-by-step explanation:

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7 0
3 years ago
The sides of the rectangle are in the ratio of 4:7. If its length is 31.5 in., find the width, the perimeter, and the area of th
AveGali [126]
Let \ell the length and w the width. By the ratio of the sides:

\dfrac{w}{\ell}=\dfrac{4}{7}\Longrightarrow \dfrac{w}{31.5}=\dfrac{4}{7}\Longrightarrow w=\dfrac{4\cdot31.5}{7}\Longrightarrow \boxed{w=18~in.}

Now, we'll find the perimeter p. We'll use the formula below:

p=2(\ell+w)\\\\
p=2(31.5+18)\\\\
p=2\cdot49.5\\\\
\boxed{p=99~in.}

The area of a rectangle is S=w\cdot\ell. Then:

S=w\cdot\ell\\\\
S=18\cdot31.5\\\\
\boxed{S=567~in.^2}
8 0
4 years ago
Read 2 more answers
Please answer the WHOLE question and explain!
exis [7]

The total weight of candies is unknown. Let x = the total weight of candies.

"One student ate 3/20 of all candies and another 1.2 lb":

The first student ate (3/20)x plus 1.2 lb which is 0.15x + 1.2.

"The second student ate 3/5 of the candies and the remaining 0.3 lb."

The second student ate (3/5)x and 0.3 lb which is 0.6x + 0.3.

Altogether the 2 students ate 0.15x + 1.2 + 0.6x + 0.3.

That was all the amount of candies, so that sum equals x.

0.15x + 1.2 + 0.6x + 0.3 = x

Now we solve the equation for x to find what the total amount of candies was.

0.75x + 1.5 = x

-0.25x = -1.5

x = 6

The total amount of candies was 6 lb.

The first student ate 0.15x + 1.2 = 0.15(6) + 1.2 = 0.9 + 1.2 = 2.1, or 2.1 lb of candies.

The second student ate 0.6x + 0.3 = 0.6(6) + 0.3 = 3.6 + 0.3 = 3.9, or 3.9 lb of candies.

Answer: The first student ate 2.1 lb of candies, and the second student ate 3.9 lb of candies.

7 0
4 years ago
Suppose the p-value is 0.1038. what is the correct interpretation of this p-value in context?
Basile [38]

The p value 0.1038 represent the proportion of students who use drugs at this college is equal to 0.157, the probability of getting a statistic as extreme or more extreme as that observed is 0.1038.

According to the statement

we have given that the P value and we have to find the correct interpretation of this p-value in context.

So, For this purpose, we know that the

The P - Value is the In null-hypothesis significance testing, the p-value is the probability of obtaining test results at least as extreme as the result actually observed.

And in the given statement ,

The given p value is 0.1038.

And this p value is a If the proportion of students who use drugs at this college is equal to 0.157, the probability of getting a statistic as extreme or more extreme as that observed is 0.1038.

So, The p value 0.1038 represent the proportion of students who use drugs at this college is equal to 0.157, the probability of getting a statistic as extreme or more extreme as that observed is 0.1038.

Learn more about P value here

brainly.com/question/4621112

Disclaimer: This question was incomplete. Please find the full content below.

Question:

Suppose the p-value is 0.1038. What is the correct interpretation of this p-value in context?

a.) If the proportion of students who use drugs at this college is greater than 0.157, the probability of getting a statistic as extreme or more extreme as that observed is 0.1038.

b.) There is a 0.1038 probability that the proportion of students who use drugs at this college is greater than 0.157.

c.) If the proportion of students who use drugs at this college is equal to 0.157, the probability of getting a statistic as extreme or more extreme as that observed is 0.1038.

d.) There is a 0.1038 probability that the proportion of students who use drugs at this college is equal to 0.157.

#SPJ4

3 0
2 years ago
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