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Alex777 [14]
4 years ago
5

Multiply using mental math 20×72×5

Mathematics
1 answer:
kondor19780726 [428]4 years ago
3 0
20 x 5 = 100  and 100 x 72 = 7200
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Triangle RST has vertices located at R (2, 3), S (4, 4), and T (5, 0). Part A: Find the length of each side of the triangle. Sho
deff fn [24]

Answer:

(a) Side lengths

RS = \sqrt{5}     ST = \sqrt{17}    RT = \sqrt{18}

(b) Slope

RS = \frac{1}{2}      RT = 1      ST = -4

(c) Scalene triangle

Step-by-step explanation:

Given

R = (2,3)

S = (4,4)

T = (5,0)\\

Solving (a): Length of each side

This is calculated using distance formula

d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

So, we have:

RS = \sqrt{(4 - 2)^2 + (4 - 3)^2}

RS = \sqrt{5}

ST = \sqrt{(5 - 4)^2 + (0- 4)^2}

ST = \sqrt{17}

RT = \sqrt{(5 - 2)^2 + (0 - 3)^2}

RT = \sqrt{18}

Solving (b): The slope of each side

This is calculated using:

m = \frac{y_2 - y_1}{x_2 - x_1}

So, we have:

RS = \frac{4- 3}{4- 2}

RS = \frac{1}{2}

RT = \frac{0 - 3}{5- 2}

RT = \frac{ - 3}{- 3}

RT = 1

ST = \frac{0 - 4}{5- 4}

ST = \frac{- 4}{1}

ST = -4

Solving (c): Classify the triangle

In (a), we have:

RS = \sqrt{5}

ST = \sqrt{17}

RT = \sqrt{18}

None of the sides are equal;

The triangle is scalene

5 0
3 years ago
A factory increased its production by 22.5% and produced 4900 tonnes .How many tonnes was it producing before?​
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Answer:

It produced 3797.5 tons before.

22.5% of 4900 is 1102.5

That subtracted from 4900 is 3797.5 tons

7 0
4 years ago
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7y + 4x + 4 - 2x + 8 what is the constant
N76 [4]
4 and 8::::::: because they have no variable u can add 4 and 8 which would be 12
3 0
4 years ago
What is the solution of this system of linear equations?
creativ13 [48]

Answer: D

Step-by-step explanation:

Consider the first equation. Subtract 3x from both sides.

y−3x=−2

Consider the second equation. Subtract x from both sides.

y−2−x=0

Add 2 to both sides. Anything plus zero gives itself.

y−x=2

To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.

y−3x=−2,y−x=2

Choose one of the equations and solve it for y by isolating y on the left hand side of the equal sign.

y−3x=−2

Add 3x to both sides of the equation.

y=3x−2

Substitute 3x−2 for y in the other equation, y−x=2.

3x−2−x=2

Add 3x to −x.

2x−2=2

Add 2 to both sides of the equation.

2x=4

Divide both sides by 2.

x=2

Substitute 2 for x in y=3x−2. Because the resulting equation contains only one variable, you can solve for y directly.

y=3×2−2

Multiply 3 times 2.

y=6−2

Add −2 to 6.

y=4

The system is now solved.

y=4,x=2

6 0
3 years ago
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