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Katen [24]
3 years ago
15

Mr. Eanes spent $205.60 at Target. There was a 15% off sale. How much discount did he get?

Mathematics
2 answers:
mojhsa [17]3 years ago
8 0

Answer:

$174.76

Step-by-step explanation:

205.60                     205.60

x 0.15        ---->        - 30.84

-------------   Next      ---------------

30.84                        $174.76

Hope this helped!

Delicious77 [7]3 years ago
4 0

Answer:

He got $30.84 off.

Step-by-step explanation:

15% of 205.60 is 174.76.

205.60 minus 174.76 is 30.84.

I'm not entirely sure this is right, but I still tried. Sorry if it's wrong.

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The answer is 421.612
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3 years ago
find the circumference of the circle. d=23 in. a)144.44 in b)1661.06 in c)36.11 in d)72.22 in e)415.27 in
snow_lady [41]

Circumference of a circle = \pi (diameter)

Diameter = 23 in.

Plug in the diameter = 23 in in the formula of circumference given above

Circumference of a circle = \pi (23)

Circumference of a circle = 23 \pi

\pi = 3.14

Circumference of a circle = 23 (3.14)

Circumference of a circle = 72.22 in

Option D is the answer

4 0
3 years ago
Read 2 more answers
A sample of salary offers (in thousands of dollars) given to management majors is: 48, 51, 46, 52, 47, 48, 47, 50, 51, and 59. U
balu736 [363]

Answer:

Step-by-step explanation:

number of samples, n = 10

Mean = (48 + 51 + 46 + 52 + 47 + 48 + 47 + 50 + 51 + 59)/10 = 49.9

Standard deviation = √(summation(x - mean)/n

Summation(x - mean) = (48 - 49.9)^2 + (51 - 49.9)^2 + (46 - 49.9)^2+ (52 - 49.9)^2 + (47 - 49.9)^2 + (48 - 49.9)^2 + (47 - 49.9)^2 + (50 - 49.9)^2 + (51 - 49.9)^2 + (59- 49.9)^2 = 128.9

Standard deviation = √128.9/10 = 3.59

Confidence interval is written in the form,

(Sample mean - margin of error, sample mean + margin of error)

The sample mean, x is the point estimate for the population mean.

Margin of error = z × s/√n

Where

s = sample standard deviation

From the information given, the population standard deviation is unknown and the sample size is small, hence, we would use the t distribution to find the z score

In order to use the t distribution, we would determine the degree of freedom, df for the sample.

df = n - 1 = 10 - 1 = 9

Since confidence level = 95% = 0.95, α = 1 - CL = 1 – 0.95 = 0.05

α/2 = 0.05/2 = 0.025

the area to the right of z0.025 is 0.025 and the area to the left of z0.025 is 1 - 0.025 = 0.975

Looking at the t distribution table,

z = 2.262

Margin of error = 2.262 × 3.59/√10

= 2.57

the lower limit of this confidence interval is

49.9 - 2.57 = 47.33

the lower limit of this confidence interval is

49.9 + 2.57 = 52.47

So it is false

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