0.1 m/s^2 (final velocity-initial velocity) and then divide with the time taken
I only know P and V and P is pressure and V is volume
as we know that velocity= displacement/change in time
hence velocity here is= 11-3/12-0
=8/12
=2/3
=0.667m/s
hopefully i am right
Answer:
47 miles
Explanation:
From the diagrammatic representation below;we can observe the illustration of the question.
after two hours;
The first ship = 16 miles per hour × 2 hours = 32 hours
the second ship = 11 miles per hour × 2 hours = 22 hours
to solve for ΔQPR in the diagram; we have;
∠ P = 13° + (2nd quadrant) + 15°
∠ P = 13° + 90° + 15°
∠ P = 118°
To solve for the distance apart the two ship, we can see from the diagram that it is "p". So, using cosine rule; we have:
p² = q² + r² - 2qr Cos P
p² = 22² + 32² - 2(22)(32) Cos 118°
p² = 484 + 1024 - (1408) (-0.4695)
p² = 1508 + 661.056
p² = 2169.056
p = 
p = 46.5731252
p ≅ 47 miles
∴ The ships will be 47 miles far apart after 2 hours.
Answer:
does this even make sense
Explanation: