A lunar eclipse occurs only when the Moon is new. A lunar eclipse occurs only when the Moon is new. True False

The sun is At the equator during the spring equinox

valina [46]

Answer:

Vertical

Explanation:

The sun would be vertical to the earths equator.

6 0

3 years ago

Four monitoring wells have been placed around a leaking underground storage tank. The wells are located at the corners of a 1-ha

Readme [11.4K]

Answer:

direction : West to East

magnitude : 6.0 * 10^-3

Explanation:

Given data :

Four ( 4 ) monitoring wells

location of wells = corners of 1-ha square

Total piezometric head in each well ;

NE corner = 30.0 m ;

SE corner = 30.0 m;

SW corner = 30.6 m;

NW corner = 30.6 m.

Calculate for the magnitude and direction of the hydraulic gradient

first step ; calculate for area

Area = ( 1 -ha ) ( 10^4 m^2/ha )

= 1 * 10^4 m^2

Distance between the wells = length of side

= √( 1 * 10^4 ) m^2

= 100 m

Direction of Hydraulic gradient is from west to east because the total piezometric head in the west = Total piezometric head in the east

Next determine The magnitude of the hydraulic gradient

= ( 30.6 - 30 ) / 100

= 6.0 * 10^-3

8 0

3 years ago

A 5 kg toy is tied to a rope where the tension measures 150 N. What is the weight of the object?

elena-s [515]

Formula from physics to get the answer.

4 0

3 years ago

A particle of mass 4.0 kg is constrained to move along the x-axis under a single force F(x) = −cx3 , where c = 8.0 N/m3 . The pa

Pie

Answer:4.58 m/s

Explanation:

Given

mass of Particle $m=4 kg$

$F=-cx^3$

$a=\frac{F}{m}$

$a=-\frac{cx^3}{m}$

$a=-\frac{8x^3}{4}$

$a=-2x^3$

$v\frac{\mathrm{d} v}{\mathrm{d} x}=-2x^3$

$vdv=-2x^3dx$

integrating

$\int_{6}^{v_b}vdv=\int_{1}^{-2}-2x^3dx$

$\frac{v_b^2-6^2}{2}=-\frac{1}{2}\left [ \left ( -2\right )^4-\left ( 1\right )^4\right ]$

$\frac{v_b^2-36}{2}=-0.5\times 15$

$v_b^2=36-15$

$v_b=\sqrt{21}$

$v_b=4.58 m/s$

6 0

3 years ago

A 300 MHz electromagnetic wave in air (medium 1) is normally incident on the planar boundary of a lossless dielectric medium wit

Masja [62]

Answer:

Wavelength of the incident wave in air = 1 m

Wavelength of the incident wave in medium 2 = 0.33 m

Intrinsic impedance of media 1 = 377 ohms

Intrinsic impedance of media 2 = 125.68 ohms

Check the explanation section for a better understanding

Explanation:

a) Wavelength of the incident wave in air

The frequency of the electromagnetic wave in air, f = 300 MHz = 3 * 10⁸ Hz

Speed of light in air, c = 3 * 10⁸ Hz

Wavelength of the incident wave in air:

$\lambda_{air} = \frac{c}{f} \\\lambda_{air} = \frac{3 * 10^{8} }{3 * 10^{8}} \\\lambda_{air} = 1 m$

Wavelength of the incident wave in medium 2

The refractive index of air in the lossless dielectric medium:

$n = \sqrt{\epsilon_{r} } \\n = \sqrt{9 }\\n =3$

$\lambda_{2} = \frac{c}{nf}\\\lambda_{2} = \frac{3 * 10^{6} }{3 * 3 * 10^{6}}\\\lambda_{2} = 1/3\\\lambda_{2} = 0.33 m$

b) Intrinsic impedances of media 1 and media 2

The intrinsic impedance of media 1 is given as:

$n_1 = \sqrt{\frac{\mu_0}{\epsilon_{0} } }$

Permeability of free space, $\mu_{0} = 4 \pi * 10^{-7} H/m$

Permittivity for air, $\epsilon_{0} = 8.84 * 10^{-12} F/m$

$n_1 = \sqrt{\frac{4\pi * 10^{-7} }{8.84 * 10^{-12} } }$

$n_1 = 377 \Omega$

The intrinsic impedance of media 2 is given as:

$n_2 = \sqrt{\frac{\mu_r \mu_0}{\epsilon_r \epsilon_{0} } }$

Permeability of free space, $\mu_{0} = 4 \pi * 10^{-7} H/m$

Permittivity for air, $\epsilon_{0} = 8.84 * 10^{-12} F/m$

ϵr = 9

$n_2 = \sqrt{\frac{4\pi * 10^{-7} *1 }{8.84 * 10^{-12} *9 } }$

$n_2 = 125.68 \Omega$

c) The reflection coefficient,r and the transmission coefficient,t at the boundary.

Reflection coefficient, $r = \frac{n - n_{0} }{n + n_{0} }$

You didn't put the refractive index at the boundary in the question, you can substitute it into the formula above to find it.

$r = \frac{3 - n_{0} }{3 + n_{0} }$

Transmission coefficient at the boundary, t = r -1

d) The amplitude of the incident electric field is $E_{0} = 10 V/m$

Maximum amplitudes in the total field is given by:

$E = tE_{0}$ and $E = r E_{0}$

E = 10r, E = 10t

3 0

3 years ago