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Stells [14]
3 years ago
12

How to find the length of each leg with a formula of m

Mathematics
1 answer:
Bas_tet [7]3 years ago
5 0

Answer:

sksksk just mnb mmmm

Step-by-step explanation:

mmmmmmbnnheew

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10 POINST!!!<br> What is the area of quadrilateral QRST if QS=18 and RT=24? Show your work.
Allisa [31]

Answer:

area= 1/2 × d1 ×d2

d = diagonal

area= 1/2 ×24×18 =216 unit^2

6 0
3 years ago
How wold you put 4/1 as a fraction?
valentinak56 [21]
4/1 is 4. It's the same as saying 4 divided by 1

7 0
4 years ago
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52 &lt; x + 24? how do i work this?
Lostsunrise [7]

Answer: 28

Step-by-step explanation:

52

Begin by isolating x. To do this, you can substract 24 on both sides.

-24+52

28

That's your answer. Any value of ''x'' must be greater than 28 for this inequality to be true.

6 0
3 years ago
The daily average temperature in Santiago, Chile, varies over time in a periodic way that can be modeled approximately by a trig
natali 33 [55]

Answer:

a) the trigonometric function is;

y = 7.5 sin ( \frac{2 \pi}{365}t + \frac{337 \pi}{730})+ 21.5

b) y = 28.36^0 \ C    ( to two decimal places)

Step-by-step explanation:

This data can be represented by the sinusoidal function of the form :

\mathbf{y = A sin (Bt -C)+D}

where A = amplitude and which can be determined via the formula:

A = \dfrac{largest \ temperature -  lowest \ temperature}{2}

A = \dfrac{29-14}{2}

A = \dfrac{15}{2}

A = 7.5° C

where B = the frequency;

Since the data covers a period of 3 days ; then \dfrac{2 \pi}{B } =365

B = \dfrac{2 \pi}{365}   ( where 365 is the time period )

The vertical shift is found by the equation D;

D =  \frac{largest \ temperature + lowest \ temperature}{2}

D = \frac{29+14}{2}

D = 21.5

Replacing the values of A ; B and D into the above sinusoidal function; we have :

y = 7.5 sin (\frac{2 \pi}{365}t -C) + 21.5

From the question; when it is 7th of the year ( i.e January 7);

t =  7 and the temperature (y) = 29° C

replacing that too into the above equation; we have:

29= 7.5 sin (\frac{2 \pi}{365}*7 -C) + 21.5

29= 7.5 sin (\frac{14 \pi}{365} -C) + 21.5

\frac{29-21.5}{7.5}=  sin (\frac{14 \pi}{365} -C)

1=  sin (\frac{14 \pi}{365} -C)

sin^{-1}(1)=   (\frac{14 \pi}{365} -C)

\frac{\pi}{2}=   (\frac{14 \pi}{365} -C)

C=   (\frac{14 \pi}{365} -\frac{\pi}{2})

C=   (\frac{28 \pi- 365 \pi}{730} )

C=  \frac{-337 \pi}{730}

Thus; the trigonometric function is;

y = 7.5 sin ( \frac{2 \pi}{365}t + \frac{337 \pi}{730})+ 21.5

Similarly; to determine the temperature o Jan 31; i.e when t= 31 ; we have :

y = 7.5 sin ( \frac{2 \pi}{365}*31+ \frac{337 \pi}{730})+ 21.5

y = 7.5 sin ( \frac{62 \pi}{365}+ \frac{337 \pi}{730})+ 21.5

y = 7.5 sin ( \frac{124 \pi+ 337 \pi }{730})+ 21.5

y = 7.5 sin ( \frac{461 \pi }{730})+ 21.5

y = 7.5 *( 0.915)+ 21.5

y = 6.8689+ 21.5

y = 28.36^0 \ C    ( to two decimal places)

7 0
3 years ago
Read 2 more answers
Which statement about the point (2, 0) is true?
ICE Princess25 [194]

\qquad \qquad\huge \underline{\boxed{\sf Answer}}

The Correct choice is : C

\qquad \sf  \dashrightarrow \: it \:  \: is  \: \: on  \: \: the \: x  - axis

As we can observe, the y - coordinate ( ordinate ) of the given point (2 , 0) is 0. so it's obvious that it's distance from x - axis is Zero. In other words we can say that the point is lying on x - axis.

8 0
2 years ago
Read 2 more answers
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