Find the equation of the line which passes through the point (−2,−5) and is parallel to the line −3x+5y=−4.
2 answers:
You first slice for y on the first equations, then use the point slope formula which is y-y1=m(x-x1) it’s parallel because it had the same slope
-3x+5y=-4
5y=3x-4
Y=3/5x-4/5
When it parallel to the line y=3/5x-4/5
It can be y=-3/5x+b
-5=6/5+b
B=-5-6/5=-25/5-6/5=-31/5
Y=-3/5x-31/5
3/5x+y=-31/5
Multiply 5
3x+5y=-31
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