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3 years ago

Find the equation of the line which passes through the point (−2,−5) and is parallel to the line −3x+5y=−4.

2 answers:

7 0

You first slice for y on the first equations, then use the point slope formula which is y-y1=m(x-x1) it’s parallel because it had the same slope

leonid [27]3 years ago

4 0

-3x+5y=-4
5y=3x-4
Y=3/5x-4/5

When it parallel to the line y=3/5x-4/5

It can be y=-3/5x+b

-5=6/5+b

B=-5-6/5=-25/5-6/5=-31/5

Y=-3/5x-31/5

3/5x+y=-31/5

Multiply 5

3x+5y=-31

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Solve 2x2 + 20x = −38. (1 point)

RoseWind [281]

Answer:

The solutions are $x=-5+\sqrt{6}$ and $x=-5-\sqrt{6}$

Step-by-step explanation:

we have

$2x^{2} +20x=-38$

Divide by $2$ both sides

$x^{2} +10x=-19$ ------> $x^{2} +10x+19=0$

we know that

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^{2} +10x+19=0$

$a=1\\b=10\\c=19$

substitute

$x=\frac{-10(+/-)\sqrt{10^{2}-4(1)(19)}}{2(1)}$

$x=\frac{-10(+/-)\sqrt{100-76}}{2}$

$x=\frac{-10(+/-)\sqrt{24}}{2}$

$x=\frac{-10(+/-)2\sqrt{6}}{2}$

$x1=\frac{-10(+)2\sqrt{6}}{2}=-5+\sqrt{6}$

$x2=\frac{-10(-)2\sqrt{6}}{2}=-5-\sqrt{6}$

8 0

3 years ago

Read 2 more answers

The measure of angle D is 5 times the measure of angle E. The two angles are supplementary. Find the measure of each angle

steposvetlana [31]

Angle e = x angle d = 5x supplementary means they add up to 180
x + 5x =180
6x = 180
6x/6 = 180/6
x = 30
so angle e = 30 and angle d = 5(30) = 150

4 0

3 years ago

1.6.PS-25

gtnhenbr [62]

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8 0

3 years ago

What is the MEAN of 86,90,93,85,79,92?

rodikova [14]

The mean to your problem is 87.5

8 0

3 years ago

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Plz help me schools basically here for me

nevsk [136]

Here's what i did:

I broke down the fraction entirely.

3 / 5 = 6 / 10

divide 6 by two and divide 18 by two. This makes 3 / 10 = 9.

divide 3 by three and 9 by three, making 1 / 10 = 3.

if you need 7 / 10 of the number (30) then do 3*7.

The answer is 21.

8 0

3 years ago