Answer:

So then we have approximately 14% of the values higher than 95.5
Step-by-step explanation:
For this case we assume that the info is given on the figure attached.
From this figure we have the following frequencies for each class
Class Frequency
___________________________
70.5-75.5 13
75.5-80.5 7
80.5-85.5 6
85.5-90.5 10
90.5-95.5 19
95.5-100.5 9
____________________________
Total 64
So we have a total of 64 values and we want to find the percentage of students that scored higher than 95.5 so we can use the formula of relative change and we got:

So then we have approximately 14% of the values higher than 95.5
Answer:
see explanation
Step-by-step explanation:
Under a reflection in the x- axis
a point (x, y ) → (x, - y ), hence
F(- 1, 9) → F'(- 1, - 9)
G(- 2, 1) → G'(- 2, - 1)
H(- 7, 4) → H'(- 7, - 4)
After 2 weeks Ramona will have twice as much as Claire.
work
claire 8$
8*2=16
12*2=24
The answer is .426 or .43 depending on what you round to. The equation for density is
D=m/v so D= 239.2/92 will give you the answer to your problem.