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Whitepunk [10]
3 years ago
13

Reflect over the x-axis: f(x) = x²

Mathematics
1 answer:
Leni [432]3 years ago
3 0

Answer:

f(x)= -x^2

Step-by-step explanation:

the reflection adds a negative sign to the equation

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Solve the equation for x.<br> x2 = 484<br> X = +
Greeley [361]

Step-by-step explanation:

{x}^{2}  = 484 \\\huge x =  \pm \sqrt{ \boxed{484}}  =   \red {\pm \boxed{  22}}

8 0
3 years ago
PLEASE HELP ME FOR BRAINLIEST Reduce to simplest form. 6/3+(-1/6)
Leni [432]

Answer: 1 5/6, or 11/6, or 1.83333333

Step-by-step explanation:

\frac{6}{3} + -\frac{1}{6}

6/3 is 2.

Thus, the answer is 2 - 1/6 or 1 5/6

7 0
3 years ago
Read 2 more answers
Points Q and P on the coordinate grid below show the positions of two midfield players of a soccer team:
Sladkaya [172]

Answer:

Q is P reflected across the y-axis; only the signs of the y-coordinates of P and Q are different.

Step-by-step explanation:

3 0
3 years ago
Between the years of 1947 and 1956, earthenware jars containing what are known as the Dead Sea Scrolls were found in caves along
lidiya [134]

Answer:

They are right, the time calculated using the exponential decay equation is 1948.6 years.

Step-by-step explanation:

The time can be calculated using the exponential decay equation:

N_{(t)} = N_{0}e^{-\lambda t}     (1)

<u>Where</u>:

N(t): is the quantity of C-14 at time t

N₀: is the initial quantity of C-14

λ: is the decay constant  

The decay constant is:

\lambda = \frac{ln(2)}{t_{1/2}}   (2)    

By entering equation (2) into (1) and solving for t, we have:

t = \frac{t_{1/2}*ln(N_{t}/N_{0})}{ln(2)} = \frac{5730*ln(0.79)}{ln(2)} = 1948.6 y

Therefore, the time of the scrolls estimated by the archeologists is right, since the time calculated using the exponential decay equation is 1948.6 years.      

I hope it helps you!

8 0
3 years ago
Can someone please help me, this is for summer school and I need fast replies, I have 29 other question like these, please help.
Yuri [45]

\implies {\blue {\boxed {\boxed {\purple {\sf { \:  A. \:- 8 {v}^{4}  + 3 {v}^{3}  + v + 5}}}}}}

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}

(4 + 6v + 3 {v}^{3} ) - (5v + 8 {v}^{4}  - 1)

➼\: 4 + 6v + 3 {v}^{3}  - 5v  -  8 {v}^{4}  + 1

Combining like terms, we have

➼\: - 8 {v}^{4}  + 3 {v}^{3}  + 6v - 5v + 4 + 1

➼\:  - 8 {v}^{4}  + 3 {v}^{3}  + v + 5

<h3 />

\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}

7 0
3 years ago
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