a = 5 in
b = 12 in
c = 15 in
the lengths of the sides a, b and c
the perimeter is P = a + b + c = 5 + 12 + 15 = 32 in
let the dimensions of the new triangle be
a1 = (1/5)*5 in
b1 = (1/5)*12 in
c1 = (1/5)*15 in
the perimeter is P1 = a1 + b1 + c1 = (1/5)5 + (1/5)12 + (1/5)15 = (1/5)(5 + 12 + 15) = (1/5)P1
P1 = (1/5)P
P1/P = 1/5 = a/a1 = b/b1 = c/c1
the ratio of the perimeters is equal to the ratio of the corresponding sides.
9514 1404 393
Answer:
15/17
Step-by-step explanation:
cos(arctan(8/15)) = 15/17
__
You could assume the ratio values 8 and 15 represent the opposite and adjacent sides of a right triangle. Then the hypotenuse is ...
h = √(8² +15²) = √289 = 17
The cosine is the ratio of the adjacent side to the hypotenuse, so is ...
cos(x) = 15/17
<span>X+2a = 16+aX-6a
8X - 16 = aX-2a
8(X-2) = a(X-2)
</span><span>(X-2)/<span>(X-2)</span> = a/8
1 = a/8
a= 8
</span>
Answer:
15=-6c-3d
Step-by-step explanation:
If 15=-3(2c+d)
=15=(-3×2c) - (-3×d)
=15=-6c-3d
