2 years ago

How do you solve x+2a=16+ax-6a ?

Mathematics

1 answer:

nasty-shy [4]2 years ago

3 0

X+2a = 16+aX-6a
8X - 16 = aX-2a
8(X-2) = a(X-2)
(X-2)/(X-2) = a/8
1 = a/8
a= 8

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2 years ago

Find an approximate equation y=ab^x with the coordinates (0, 4) (3, 95)

bogdanovich [222]

We have $y=ab^{x}$

Plug in $(0, 4)$ :
$4=ab^{0}$ ⇒ $4=a$
So we now have $a$

Plug in $(3, 95)$ :
$95=4b^{3}$
⇒ $b^{3}=\frac{95}{4}$
⇒ $b=\sqrt[3]{\frac{95}{4}}$
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So we get
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or, in decimal form,
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