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Agata [3.3K]
3 years ago
10

Look at the quadratic equation below. x2 - 10x + 16 = -5 What is this quadratic equation written in standard form? A.5x2 + 10x -

16 = 0 B.5x2 - 10x + 16 = 0 C.x2 - 10x + 11 = 0 D.x2 - 10x + 21 = 0
Mathematics
1 answer:
ollegr [7]3 years ago
7 0
Ax^2+bx+c=0 is the standard form, so we add 5 to both sides to get 

1*x^2+(-10)x+21=0
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AleksAgata [21]
For 10 here is the answer and for 9 i’ll reply to my comment

3 0
3 years ago
Find three points on the parabola.<br> x^2−6x−4y+5=0
aleksley [76]

Answer:

(0,1.25), (1,0), (-1,3)

Step-by-step explanation:

6 0
3 years ago
Look at the figure. Complete the statement and justify your answer.VT=
egoroff_w [7]

Answer:

(C)

Step-by-step explanation:

From the given statement, \overline{VT} ≅\overline{VX} by the converse of the isosceles theorem as it states that if two angles are congruent in the triangle, then the two sides opposite to those equal angles will also be congruent that is \overline{VT} ≅\overline{VX}.

Hence, Option C is correct.

Rest of the options are not correct as the reflexive property states that any geometric figure, any angle or any line segment has same size and shape. NEither  \overline{VT} is equal to \overline{VX} nor \overline{TX} by reflexive property as the condition is not fulfiiled.

7 0
3 years ago
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Which one is right. I am lost and I need help
Lubov Fominskaja [6]

Reflection across y=x is a special case transformation


(x,y) \rightarrow (y,x)


The original triangle has vertices A(-5,1), B(-4,3), C(-2,1), D(-3,-1) so the transformed triangle has vertices


A'(1,-5), B'(3,-4), C'(1,-2), D'(-1,-3)


Choice A'(1,-5)




8 0
4 years ago
Please help and show your work!
Dahasolnce [82]
Its 78 because you multiply 3 and 26
3 0
3 years ago
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