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AleksandrR [38]
3 years ago
10

What is 345,000 in expanded form

Mathematics
1 answer:
Georgia [21]3 years ago
8 0
All u have to do is put put them with zeros and add them up like this 300,000 + 40,000 + 5,000
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When dividing 1 by a number N to produce a decimal, what is the maximum size of the repeating portion?
AnnZ [28]

Great question.  The answer is N-1.

Think about doing long division.  We append a 0, get another digit in the quotient, multiply and subtract to get a remainder.  We can assume that remainder is not zero because then we wouldn't have a repeating decimal.   At each step the remainder has to be less than N, because we're dividing by N.

So there are N-1 possibilities for the remainder.  On the off chance we generate N-1 digits and N-1 remainders and none repeat, we know the next one will repeat, because we've already generated all the possible remainders.  

So the largest size of the repeating portion is N-1.   This maximum happens first for 1/7.

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3 years ago
Sam is 12. In four years, his age will be 2/3 the age of his cousin Lupe. How old will Lupe be in two years?
Sliva [168]

Answer:

8

Step-by-step explanation:

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what is math in your visionary state what do you think of when reminded of math I am specifacly asking you​
Zinaida [17]

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4 years ago
F(x)=4x squared −7x+7, Find f(2)
Lana71 [14]

Answer: 9

Step-by-step explanation:

4x²-7x+7   f(2)=4*(2)^2-7(2)+7=16-14+7=9

7 0
3 years ago
In this question, i is a unit vector due east and j is a unit vector due north. A cyclist rides at a speed of 4 m/s on a bearing
d1i1m1o1n [39]

<u>Answer:</u>

a) 1.04i + 3.86j

b) magnitude = 8; bearing = 302.7°

<u>Step-by-step explanation:</u>

a)

The  first diagram represents the velocity vector of the cyclist.

To express this vector in the form xi + yj, we have to find the components of the vector in the horizontal (i) and vertical (j) directions.

If we consider the horizontal component of the vector to be x, and the vertical component to be y, then:

• horizontal component ⇒ sin (15^{\circ}) = \frac{x}{4}

                                       ⇒ x = 4\space\ sin(15^{\circ})

                                       ⇒ x \approx \bf 1.04

• vertical component ⇒ cos(15^{\circ}) = \frac{y}{4}

                                   ⇒ y = 4 \space\ cos(15^{\circ})

                                   ⇒ y \approx \bf 3.86

Now that we have the values of both the horizontal and vertical component, we can write the vector in the form of xi + yj:

vector ⇒ 1.04i + 3.86j

b)

The second diagram shows the first vector (red), the second vector (blue), and the resultant vector <em>v</em> (black). The dashed lines represent the components of the respective vectors.

To add two vectors given their magnitudes and direction, we have to add their components.

In order to find the horizontal and vertical components of the given vectors, we can use a method similar to that used above, so that:

○ For the first vector (magnitude 6):

• horizontal component ⇒ x = 6 \space\ sin (60^{\circ})

                                       ⇒ \bf 5.2

• vertical component ⇒ y = 6 \space\ cos(60^{\circ})

                                   ⇒ y = \bf 3

○ For the second vector (magnitude 2):

• horizontal component ⇒ x = 2 \space\ cos (40^{\circ})

                                       ⇒ \bf 1.5

• vertical component ⇒ y = 2 \space\ sin(40^{\circ})

                                   ⇒ \bf 1.3

Now we can add the respective components together:

v = 5.2i + 3j  +  1.5i + 1.3j

 ⇒ (5.2 + 1.5)i + (3 + 1.3)j

 ⇒  6.7i + 4.3j

∴ Magnitude of v ⇒ |v| = \sqrt{(6.7)^2 + (4.3)^2}

                             ⇒ |v| \approx \bf 8

To find the bearing of <em>v</em>, we have to first calculate the angle marked \alpha:

tan \alpha = \frac{4.3}{6.7}

⇒ \alpha = tan^{-1}(\frac{4.3}{6.7})

⇒ \alpha = \bf 32.7^{\circ}

∴ Bearing = 270° + 32.7°

                = 302.7°

8 0
2 years ago
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