Remember PEMDAS is the order of operations. parenthesis,exponents,multiply,divide,add,subtract. so -8x-4x is -12x. now simplified the problem is 3(9-12x) + 8(3x+4)=11 . now I would distribute the numbers before the parentheses and it becomes 27-36x + 24x+32 =11 . now combine like terms. 59-12x =11 . subtract 59 on both sides. -12x=-48. divide -12 on both sides. x=4. :-)
Answer:
The maximum height of the volleyball is 12.25 feet.
Step-by-step explanation:
The height of the volleyball, h(t), is modeled by this equation, where t represents the time, in seconds, after that ball was set :
....(1)
The volleyball reaches its maximum height after 0.625 seconds.
For maximum height,
Put 
Now put t = 0.625 in equation (1)
So, the maximum height of the volleyball is 12.25 feet.
<span>use:S(OH) C(AH) T(OA) depending on the info given
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A. 7/11= 7 ÷ 11
B. 5/2= 5 ÷ 2
C. 9/10= 9 ÷ 10
D. 7/15= 7 ÷ 15
A fraction is just a division problem. 7/11 would be considered 7 ÷ 11 (or just 7/11) just do the same for the rest of the fractions.
Answer:
Set up your height equation, then factor or use quadratic formula to find when h(t)=0
Step-by-step explanation:
Your equation will be -16t^2+vt +h where v is the initial velocity and h is the starting height. Now either factor or quadratic equation, whichever is easier for you.
Remember that the ball is on the ground when h(t)=0 since that is the height. There will be two zeros, one is a negative number so would be before you kicked the ball, the other one will be when the ball comes back down.
