2.77778 square foot is the answer.
Solve for m by simplifying both sides of the equation, then isolating the variable.
m = 66
<u>Complete Question</u>
The usher at a wedding asked each of the 80 guests whether they were a friend of the bride or of the groom. The results are: 59 for Bride, 50 for Groom, 30 for both. Find the probability that a randomly selected person from this sample was a friend of the bride OR of the groom.
Answer:
0.9875
Step-by-step explanation:
Total Number of Guests, n(S)=80
Let the Event (a friend of the bride) =B
Let the Event (a friend of the groom) =G
n(B) =59
n(G)=50

Therefore:

Number of Guests who was a friend of the bride OR of the groom = 79
Therefore:
The probability that a randomly selected person from this sample was a friend of the bride OR of the groom.

Percentage of the weight of seeds in each bag that mariana sold last week is 10.4%.
<h3>Percentage of the weight of seeds</h3>
First step
Weight of seed and nuts last week=12/5×9
Weight of seed and nuts last week=21.6kg
Second step
Percentage of the weight of seeds=21.6 kg-19.35kg/21.6kg
Percentage of the weight of seeds=2.25kg/21.6kg
Percentage of the weight of seeds=0.104×100
Percentage of the weight of seeds=10.4%
Therefore the Percentage of the weight of seeds in each bag that mariana sold last week is 10.4%.
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