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miss Akunina [59]
2 years ago
9

A farmers productions statistics finds that it takes 2 chickens to produce 6 eggs in 24 hours. How many chickens will be needed

to produce 24 eggs in 24 hours
Mathematics
1 answer:
Lelu [443]2 years ago
7 0

Answer:

8 chickens

Step-by-step explanation:

Firstly, we need to know the number of eggs produced by a single chicken in 24 hours.

Since 2 chickens produce 6 eggs in 24hours, this means 1 chicken will produce 3 eggs in 24 hours.

Now, we need 24 eggs to be produced. Since the time is the same 24hours, meaning time is constant, the number of chickens required to produce 24 eggs will be 24/3 = 8 chickens

Hence, we can say that 8 chickens will produce 24eggs in 24 hours

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2.77778 square foot is the answer.
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3 years ago
Stuck on this one question , please help
Gnoma [55]
Solve for m by simplifying both sides of the equation, then isolating the variable.
m = 66
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2 years ago
Read 2 more answers
The usher at a wedding asked each of the 808080 guests whether they were a friend of the bride or of the groom. Here are the res
malfutka [58]

<u>Complete Question</u>

The usher at a wedding asked each of the 80 guests whether they were a friend of the bride or of the groom. The results are: 59 for Bride, 50 for Groom, 30 for both. Find the probability that a randomly selected person from this sample was a friend of the bride OR of the groom.

Answer:

0.9875

Step-by-step explanation:

Total Number of Guests, n(S)=80

Let the Event (a friend of the bride) =B

Let the Event (a friend of the groom) =G

n(B) =59

n(G)=50

n(B \cap G)=30

Therefore:

n(B \cup G)=n(B)+n(G)-n(B \cap G)\\n(B \cup G)=59+50-30\\n(B \cup G)=79

Number of Guests who was a friend of the bride OR of the groom = 79

Therefore:

The probability that a randomly selected person from this sample was a friend of the bride OR of the groom.

P(B \cup G) =\dfrac{n(B \cup G) }{n(S)} \\\\=\dfrac{79 }{80}\\\\=0.9875

4 0
3 years ago
1. A translation of a figure can be considered
topjm [15]

Answer:

B. A slide of the figure

7 0
3 years ago
6 mariana sells bags of bird food.
Aliun [14]

Percentage of the weight of seeds in each bag that mariana sold last week is 10.4%.

<h3>Percentage of the weight of seeds</h3>

First step

Weight of seed and nuts last week=12/5×9

Weight of seed and nuts last week=21.6kg

Second step

Percentage of the weight of seeds=21.6 kg-19.35kg/21.6kg

Percentage of the weight of seeds=2.25kg/21.6kg

Percentage of the weight of seeds=0.104×100

Percentage of the weight of seeds=10.4%

Therefore the Percentage of the weight of seeds in each bag that mariana sold last week is 10.4%.

Learn more about percentage here:brainly.com/question/24304697

#SPJ1

8 0
2 years ago
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