For the answer to the question above,
<span>a) Use F = k * q1 * q2 / d²
where k = 8.99e9 N·m²/C²
and q1 = -1.602e-19 C (electron)
and q2 = 1.602e-19 C (proton)
and d = distance between point charges = 0.53e-10 m
The negative result indicates "attraction".
b) Here, just use F = ma
where F was found above, and
m = mass of electron = 9.11e-31kg, if memory serves
a = radial acceleration
c) Now use a = v² / r
where a was found above
and r was given
d) period T = 2π / ω = 2πr / v
where v was found above
and r was given </span>
Answer:
2. 2N
3. -4N
4. 4N
5. 7N
Step-by-step explanation:
Answer:
domain: (-∞ , ∞)
range: (-∞, 2]
Step-by-step explanation:
the domain is the set of values of what the x value can be. This function is parabolic and upside down, it can have a range of x values from - infinity to positive infinity. The function is most likely y=-x^2 +2
range is the output (y values) the function can possibly have. the max is 2 and includes 2 so we use bracket for that. The smallest y value can reach towards negative infinity.
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Distribute 7 to both n and 1
7(n + 1) = 7n + 7
5n + 7 = 7n + 7 - 2n
Combine like terms
5n + 7 = 7n - 2n + 7
5n + 7 = 5n + 7
If you want to solve for n, subtract 7 from both sides
5n + 7 (-7) = 5n + 7 (-7)
5n = 5n
then divide 5 from both sides
5n/5 = 5n/5
n = n
Effectively, this equation is <em>unsolvable</em>
hope this helps
1. The triangle is Isosceles and acute A (since there are two equal sides and the angles are less than 90)
2. Right triangle E (since there is a right angle)
3. The triangle is obtuse scalene T (since there are no equal sides and one angle is greater than 90)
4. Right isosceles O
5. Acute equilateral N
6. Obtuse scalene T<span />
