Is there a picture of the clock?
It’s the first one welcome
Answer:
D.
Step-by-step explanation:
Answer:
![csc(\theta)=\frac{5}{3}](https://tex.z-dn.net/?f=csc%28%5Ctheta%29%3D%5Cfrac%7B5%7D%7B3%7D)
Step-by-step explanation:
If the
, then the cotangent is
, given that:
, and
.
This is important to know because if you recall the three Pythagorean identities in trigonometry, one of them involves a nice relationship between the cotangent and the cosecant of an angle:
![1+cot^2(\theta)=csc^2(\theta)](https://tex.z-dn.net/?f=1%2Bcot%5E2%28%5Ctheta%29%3Dcsc%5E2%28%5Ctheta%29)
so we can replace
with 4/3, and find what
is using that identity:
![1+cot^2(\theta)=csc^2(\theta)\\1+(\frac{4}{3})^2= csc^2(\theta)\\1+\frac{16}{9} =csc^2(\theta)\\\frac{25}{9} = csc^2(\theta)\\csc(\theta)=+/-\sqrt{\frac{25}{9}} \\csc(\theta)=+/-\frac{5}{3}](https://tex.z-dn.net/?f=1%2Bcot%5E2%28%5Ctheta%29%3Dcsc%5E2%28%5Ctheta%29%5C%5C1%2B%28%5Cfrac%7B4%7D%7B3%7D%29%5E2%3D%20csc%5E2%28%5Ctheta%29%5C%5C1%2B%5Cfrac%7B16%7D%7B9%7D%20%3Dcsc%5E2%28%5Ctheta%29%5C%5C%5Cfrac%7B25%7D%7B9%7D%20%3D%20csc%5E2%28%5Ctheta%29%5C%5Ccsc%28%5Ctheta%29%3D%2B%2F-%5Csqrt%7B%5Cfrac%7B25%7D%7B9%7D%7D%20%5C%5Ccsc%28%5Ctheta%29%3D%2B%2F-%5Cfrac%7B5%7D%7B3%7D)
Now, you have to decide on which sign to use. So consider that if the tangent was positive, so most likely you are dealing with an angle
between 0 and
, and in that quadrant, the cosecant is positive.
Therefore, pick the positive value: 5/3