Ask question

Ask question

All categories

2 years ago

10

Sierra uses 468 golf balls in a display at the sporting goods store she uses 47 golf balls in each display cases she fills and t

he number of balls left over

1 answer:

Anit [1.1K]2 years ago

3 0

9 displays, 45 balls left over.

You might be interested in

Jodi poured herself a cold soda that had an initial temperature of 45degreesF and immediately went outside to sunbathe where the

arlik [135]

The initial temperature difference of 101-45 = 56 degees declined to 101-55 = 46 degrees in 8 minutes, We can write the exponential equation for the soda's temperature as

... T = 101 -56(46/56)^(t/8) . . . . where t is in minutes

After an additional 10 minutes, we have t=18, so the soda temperature will be

... T = 101 -56(46/56)^(18/8) ≈ 65.0 . . . degrees

6 0

2 years ago

You just received your final exam score from your teacher. At the top of the exam, it says you missed three questions and got 42

Leno4ka [110]

Answer:

below

Step-by-step explanation:

I would guess that they added 42 and 45 and then added 1 for their mistake. That might be a bit of stretch, but that is what I think

3 0

2 years ago

Read 2 more answers

What direction will this parabola open?

butalik [34]

Answer:

Step-by-step explanation:

4 0

1 year ago

Given that f.x 3x-2 over x+1 g[x] x +5 evaluate f[-4] and gf [-2]

Jobisdone [24]

The value of f[ -4 ] and g°f[-2] are $\frac{14}{3}$ and 13 respectively.

<h3>What is the value of f[-4] and g°f[-2]?</h3>

Given the function;

$f(x) = \frac{3x-2}{x+1}$
$g(x)=x+5$
f[ -4 ] = ?
g°f[ -2 ] = ?

For f[ -4 ], we substitute -4 for every variable x in the function.

$f(x) = \frac{3x-2}{x+1}\\\\f(-4) = \frac{3(-4)-2}{(-4)+1}\\\\f(-4) = \frac{-12-2}{-4+1}\\\\f(-4) = \frac{-14}{-3}\\\\f(-4) = \frac{14}{3}$

For g°f[-2]

g°f[-2] is expressed as g(f(-2))

$g(\frac{3x-2}{x+1}) = (\frac{3x-2}{x+1}) + 5\\\\g(\frac{3x-2}{x+1}) = \frac{3x-2}{x+1} + \frac{5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) = \frac{3x-2+5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) = \frac{8x+3}{x+1}\\\\We\ substitute \ in \ [-2] \\\\g(\frac{3x-2}{x+1}) = \frac{8(-2)+3}{(-2)+1}\\\\g(\frac{3x-2}{x+1}) = \frac{-16+3}{-2+1}\\\\g(\frac{3x-2}{x+1}) = \frac{-13}{-1}\\\\g(\frac{3x-2}{x+1}) = 13$

Therefore, the value of f[ -4 ] and g°f[-2] are $\frac{14}{3}$ and 13 respectively.

Learn more about composite functions here: brainly.com/question/20379727

#SPJ1

6 0

1 year ago

Please help! Will give brainliest!

Zanzabum

Answer:

Step-by-step explanation:

6 0

2 years ago