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adelina 88 [10]
3 years ago
9

HELP FAST 100 POINTS: The manager of a basketball arena randomly selected 150 fans and asked if they were pleased with the new s

election of food offered in the arena. In this sample, 120 fans said that they were pleased.
How many of the 8000 fans at the game could be expected to be pleased?


7880

6400

7970

7850
Mathematics
2 answers:
V125BC [204]3 years ago
8 0

Answer:

6400 fans will be pleased.

Step-by-step explanation:

Out of 150 fans, 120 were pleased. Assuming the same ratio, out of 8000 fans, 8000x120/150 = 6400 will be pleased.


charle [14.2K]3 years ago
5 0

Answer:

6400

Step-by-step explanation:

We need to find the fraction of fans that are pleased

120 out of 150 are please

120/150  = 12/15 =4/5


We multiply this fraction by the fans at the game

4/5 * 8000 = 6400

6400 fans should be pleased

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Step-by-step explanation:

3x - 3y = 3(x-y)

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suppose the two vertical angles are measuring 6x + 15 and 4x + 32. what is the measure of each angle?
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Answer:

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Step-by-step explanation:

vertical angles are equal so,

6x+15=4x+32

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now,

4X+32

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Step-by-step explanation:

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Read 2 more answers
Select the correct answer from each drop-down menu.
finlep [7]

Answer:

Coordinates of point B are (10,-4)

Coordinates of point D are (3.6,-0.4)

Step-by-step explanation:

1) Point C(3.6, -0.4) divides in the ratio 3 : 2. If the coordinates of A are (-6, 5), the coordinates of point B are ____

Let the coordinates of B be (x_2,y_2)

Coordinates of A =(x_1,y_1)=(-6,5)

Coordinates of C=(x,y)=(3.6,-0.4)

We will use section formula over here

x=\frac{mx_2+nx_1}{m+n} , y = \frac{my_2+ny_1}{m+n}

m:n=3:2

3.6=\frac{3x_2+2(-6)}{3+2} , -0.4=\frac{3y_2+2(5)}{3+2}3.6 \times 5 = 3x_2-12, -0.4 \times 5 = 3y_2+10\\18+12=3x_2 , -2=3y_2+10\\30=3x_2 , -12=3y_2\\10=x_2, -4=y_2\\

Coordinates of B = (10,-4)

2)If point D divides in the ratio 4 : 5, the coordinates of point D are ____

(fraction)

Let the coordinates of D be (x,y)

Coordinates of A =(x_1,y_1)=(-6,5)

Coordinates of B=(x_2,y_2)=(10,-4)

We will use section formula over here

x=\frac{mx_2+nx_1}{m+n} , y = \frac{my_2+ny_1}{m+n}

m:n=3:2

x=\frac{3(10)+2(-6)}{3+2} , y=\frac{3(-4)+2(5)}{3+2}\\x=3.6,y=-0.4

Coordinates of point B are (10,-4)

Coordinates of point D are (3.6,-0.4)

4 0
3 years ago
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