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3 years ago

Which is the value of this expression when X=-2

1 answer:

6 0

A) x^2 +x -30 = 0 is factored by looking for two factors of 30 that differ by 1. We know ... 30 = 1*30 = 2*15 = 3*10 = 5*6The last two factors differ by 1, so we can factor the trinomial as (x +6)(x -5) = 0
b) The solutions are found by finding values of x that make these factors zero. The only way the product will be zero is if one or more of the factors is zero. x + 6 = 0 x = -6 . . . . . subtract 6
x - 5 = 0 x = 5 . . . . . add 5
The solutions are x = -6 or x = 5These are the values of x that will satisfy the equation (make it true). What they mean depends on the meaning of the variable and the situation the equation is a model of.

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Did I do this correctly?

butalik [34]

6/x= -2/18

Cross multiply. ( Multiply the numerators together ) . ( Multiply the denominators together (.

6*18= - 2*x

108= -2x

Divide by -2 for 108 and -2x

108/-2= -2x/2

x= -54

Answer: x= -54

6 0

3 years ago

-13=r/9+8<br> what is r equal to?

AURORKA [14]

Answer: r=(-189)

first you subtract both sides by 8 and get -21=r/9

then you multiply 9 with each side and get -189 = r

you can check by rewriting the problem with -189 as r and solving the equation

7 0

3 years ago

Need help on this thanks

rosijanka [135]

Answer:

D I think

Step-by-step explanation:

The decimal place is pushed back till both have whole numbers

3 0

3 years ago

Read 2 more answers

When a deposit of $1000 is made into an account paying 2% interest, compounded annually, the balance, $B, in the account after t

labwork [276]

Answer:

The average rate of change in the balance over the interval t = 0 to t = 5 is of $20.82 a year. This means that the balance increased by $20.82 a year over the interval t = 0 to t = 5.

Step-by-step explanation:

Given a function y, the average rate of change S of y=f(x) in an interval $(x_{s}, x_{f})$ will be given by the following equation:

$S = \frac{f(x_{f}) - f(x_{s})}{x_{f} - x_{s}}$

In this problem, we have that:

$B(t) = 1000(1.02)^{t}$

Find the average rate of change in the balance over the interval t = 0 to t = 5.

$B(0) = 1000(1.02)^{0} = 1000$

$B(5) = 1000(1.02)^{5} = 1104.08$

Then

$S = \frac{1104.08 - 1000}{5-0} = 20.82$

The average rate of change in the balance over the interval t = 0 to t = 5 is of $20.82 a year. This means that the balance increased by $20.82 a year over the interval t = 0 to t = 5.

8 0

3 years ago

Write an equation of each line in point-slope form. containing (2,1) and (3,4)

Leokris [45]

Answer:

y=3x-5

Step-by-step explanation:

This is the only line that will pass through these points.

7 0

3 years ago