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2 years ago

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The legs of a right triangle are 4 units and 7 units. What is the length of the hypotenuse? (4 points) Group of answer choices s

quare root 33 units square root 65 units 33 units 65 units

1 answer:

morpeh [17]2 years ago

5 0

Answer:

65 square root

Step-by-step explanation:

I’m smart

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Solve the compound inequality and write the solution in interval notation: 34x−3≤3 or 25(x+10)≥0.

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Answer

x≤3/17 or x≥-10

Step-by-step explanation:

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3 years ago

The volume of a cylinder is 176 π cm and its height is 11 π cm.

Liula [17]

Answer:

r = sqrt(16/pi)

Step-by-step explanation:

Cylinder formula = r^2 x pi x height

176 pi/11pi = 16

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16/ pi = r^2

r = sqrt(16/pi)

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How do you put an equation in slope-intercept form into standard or point-slope form?

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3 years ago

Suppose that a college determines the following distribution for X = number of courses taken by a full-time student this semeste

lidiya [134]

Answer:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 3*0.07 +4*0.4 +5*0.25 +6*0.28= 4.74$ In order to find the variance we need to calculate first the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 3^2*0.07 +4^2*0.4 +5^2*0.25 +6^2*0.28= 23.36$ And the variance is given by:

$Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924$

And the deviation would be:

$Sd(X) =\sqrt{0.8924} =0.9447$

Step-by-step explanation:

Previous concepts

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).

Solution to the problem

For this case we have the following distribution given:

X 3 4 5 6

P(X) 0.07 0.4 0.25 0.28

We can calculate the mean with the following formula:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 3*0.07 +4*0.4 +5*0.25 +6*0.28= 4.74$

In order to find the variance we need to calculate first the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 3^2*0.07 +4^2*0.4 +5^2*0.25 +6^2*0.28= 23.36$

And the variance is given by:

$Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924$

And the deviation would be:

$Sd(X) =\sqrt{0.8924} =0.9447$

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3 years ago

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ra1l [238]

Answer:4x14

Step-by-step explanation:

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3 years ago

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