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sineoko [7]
2 years ago
12

When the angle of elevation of the sun is 78 degrees, a tree casts a 13 foot shadow. How tall is the tree?

Mathematics
1 answer:
oksian1 [2.3K]2 years ago
4 0

Answer: 61.16 ft

Step-by-step explanation:

We can think in this situation as a triangle rectangle.

where:

The height of the tree is one cathetus

The shadow of the tree is the other cathetus.

We know that the angle of elevation of the sun is 78°, an angle of elevation is measured from the ground, then the adjacent cathetus to this angle is the shadow of the tree. And the opposite cathetus will be the height of the tree.

Now we can remember the relationship:

Tg(A) = (opposite cathetus)/(adjacent cathetus)

Where:

A = 78°

Adjacent cathetus = 13ft

opposite cathetus = height of the tree = H

Then we have the equation:

Tg(78°) = H/13ft

Tg(78°)*13ft = H = 61.16 ft

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3 years ago
How do I solve this?
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Answer:

Answer A represents this

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Step-by-step explanation:

Isolate x on each of the inequalities:

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subtract 4 from both sides

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This inequality is represented by shading the left section of the number line starting at x = -3 (make sure you draw a SOLID dot to mae clear that the point x = -3 is also included in your drawing.

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4 0
3 years ago
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5 0
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Answer:

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Step-by-step explanation:

Let´s study this as a Normal distribution.

As we know in a normal distribution the z score is = (X-μ)/(sd/sqrt(n))

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So in this case z=( X-80)/(12/sqr(9))= (X-80)/4

also we know that the effect size taken by the machine is 0.5, which is the same as the z-score

so...

0.5 = (X-80)/4 => 0.5*4 = X-80

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4 0
3 years ago
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Ad libitum [116K]

Answer:

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Step-by-step explanation:

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After that, divide by 6 since there are 6 numbers

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Have a good day :)

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