Interval notation x=-2 or x=0

Mathematics

1 answer:

STALIN [3.7K]2 years ago

3 0

I have a good record of guessing the right one so I would say #1.

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Which function has a simplified base of 4RootIndex 3 StartRoot 4 EndRoot? f(x) = 2(RootIndex 3 StartRoot 16 EndRoot) Superscript

PIT_PIT [208]

Answer:

$f(x)=4\sqrt[3]{16}^{2x}$

Step-by-step explanation:

We believe you're wanting to find a function with an equivalent base of ...

$4\sqrt[3]{4}\approx 6.3496$

The functions you're looking at seem to be ...

$f(x)=2\sqrt[3]{16}^x\approx 2\cdot2.5198^x\\\\f(x)=2\sqrt[3]{64}^x=2\cdot 4^x\\\\f(x)=4\sqrt[3]{16}^{2x}\approx 4\cdot 6.3496^x\ \leftarrow\text{ this one}\\\\f(x)=4\sqrt[3]{64}^{2x}=4\cdot 16^x$

The third choice seems to be the one you're looking for.

9 0

2 years ago

Read 2 more answers

12+90+x=180 I need help fast

Vinil7 [7]

Answer:

Step-by-step explanation:

102+x=180

x=180-102

x=78

3 0

2 years ago

5.8 km is how many meters

stepan [7]

Answer:

5,800m

Step-by-step explanation:

1 km = 1000 m

Use the SBD (small to big, divide) and BSM (big to small, multiply) method.

So, 5.8 X 1000, as we are converting km(big) to m(small) and move the decimal point corresponding to the number of zeroes = 5800m

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2 years ago

Six Republicans and four Democrats have applied for two open positions on a planning committee. Since all the applicants are qua

Dafna11 [192]

Answer:

$\displaystyle P=\frac{7}{15}=0.467$

Step-by-step explanation:

<u>Probabilities</u>

When we choose from two different sets to form a new set of n elements, we use the so-called hypergeometric distribution. We'll use an easier and more simple approach by the use of logic.

We have 6 republicans and 4 democrats applying for two positions. Let's call R to a republican member and D to a democrat member. There are three possibilities to choose two people from the two sets: DD, DR, RR. Both republicans, both democrats and one of each. We are asked to compute the probability of both being from the same party, i.e. the probability is

$P=P(DD)+P(RR)$