Answer:
13 yds
Step-by-step explanation:
the blue side starter (B) swims 29yd in the time it takes the red side starter (R) to swim 21yd
their combined distance, when they meet, is 50yd (length of pool)
they pass each other and continue to the ends of the pool (combined distance, 100yd)
they swim towards each other again, and pass a second time (combined distance, 150yd)
at this point, R has swum 63yd (3*21) -- one length plus 13yd
so RS is 13yd from the blue end
The possible values are anything between -7 and -4 so this means it would be either -5 or -6
There isn't a quotient of the division sign
Correct Question: If m∠JKM = 43, m∠MKL = (8x - 20), and m∠JKL = (10x - 11), find each measure.
1. x = ?
2. m∠MKL = ?
3. m∠JKL = ?
Answer/Step-by-step explanation:
Given:
m<JKM = 43,
m<MKL = (8x - 20),
m<JKL = (10x - 11).
Required:
1. Value of x
2. m<MKL
3. m<JKL
Solution:
1. Value of x:
m<JKL = m<MKL + m<JKM (angle addition postulate)
Therefore:

Solve for x


Subtract 8x from both sides


Add 11 to both sides


Divide both sides by 2


2. m<MKL = 8x - 20
Plug in the value of x
m<MKL = 8(17) - 20 = 136 - 20 = 116°
3. m<JKL = 10x - 11
m<JKL = 10(17) - 11 = 170 - 11 = 159°