Remember
ab+ac=a(b+c0
3x+3x+5+5
2(3x)+2(5)
2(3x+5)
2nd option
Answer:
(2,-1)
Step-by-step explanation:
Multiply first equation by 2:
10x + 2y = 18
Subtract the second equation from this so that the 2y terms cancel:
10x - 3x = 18 - 4
7x = 14
x = 2
Plug into first equation to find y:
5(2) + y = 9
10 + y = 9
y = -1
The answer is (2,-1)
Answer:
what are we actually solving for?....
anyways I had a suggestion ion know if it's right or wrong....
<em>Isolate</em><em> </em><em>the</em><em> </em><em>variable</em><em> </em><em>by</em><em> </em><em>diving</em><em> </em><em>each</em><em> </em><em>side</em><em> </em><em>by</em><em> </em><em>factor</em><em> </em><em>that</em><em> </em><em>don't</em><em> </em><em>contain</em><em> </em><em>the</em><em> </em><em>vari</em><em>able</em><em>.</em>
<em>Therefore</em><em> </em><em>x</em><em>=</em><em>7</em><em>.</em><em>2</em>
Answer:
Sydney is 44 years old
Step-by-step explanation:
<u>Step 1: Make a system of equations
</u>
d = s - 15
<em>d + s = 73
</em>
<u>Step 2: Plug in s - 15 for d in the second equation and solve
</u>
s - 15 + s = 73
2s - 15 = 73 + 15
2s / 2= 88 / 2
<em>s = 44
</em>
Answer: Sydney is 44 years old
