Answer:
Explanation:
We know that
Δr = r₁ - r₀
r₀ = 0 i + 0 j
r₁ = (162+137*Cos(31º)+137*Cos(-48º)) i + (0+137*Sin(31º)+137*Sin(-48º)) j = (371.1028 i - 31.2506 j) ft
Δr = r₁ - r₀ = (371.1028 i - 31.2506 j) - (0 i + 0 j) = (371.1028 i - 31.2506 j) ft
Magnitude:
Δr = √((371.1028)²+(-31.2506)²) = 372.4163 ft
Angle:
tan θ = (- 31.2506 / 371.1028) = -0.0839 ⇒ θ = tan⁻¹(-0.0839) = - 4.8135º
(below the horizontal).
Answer:
The K.E is maximum when the child is at the vertical position and the P.E is maximum at the extreme deviated position from the vertical.
Explanation:
- A child is swinging on swing up and down has both kinetic and potential energy.
- The total mechanical energy of the system is conserved throughout the system. At any instant the total mechanical energy is given by,
E = K.E + P.E
- The K.E is maximum when the child is at the vertical position.
- The P.E is maximum at the extreme deviated position from the vertical.
- And when K.E is maximum P.E becomes minimum and vice versa as per the law of conservation of energy.
Answer:
n = 1.76
Explanation:
According to the rule of ( n1 sin theta1 = n2 sin theta2 )
we know both angles so we insert them to the law and apply n1 = 1
so 1/2 = n2 sin 62 and we get the final answer
Refer to the diagram shown.
Given:
Define
Then the rate of change of h with respect to the vector v is
Answer: 17.7 ft per mile
