1. 0.5g*t^2 = 2010 m.
4.9t^2 = 2010.
t = 20.3 s. = Fall time.
D = Xo*t. = 193m/s * 20.3s = 3909 m.
2. V=sqrt(Xo^2+Yo^2)=sqrt(193^2+58^2) = 202 m/s.
3. Vo*t + 0.5g*t^2 = 2010 m.
58*t + 4.9*t^2 = 2010.
4.9t^2 + 58t - 2010 = 0.
Use Quadratic Formula.
t = 15.2 s. = Fall time.
D = 193m/s * 15.2s = 2934 m.
Answer:
I = 5[amp]
Explanation:
Electrical power is defined as the product of voltage by current.

where:
P = power = 1150 [W]
V = voltage = 230 [V]
I = current [amp]
Now replacing:
![1150=230*I\\I=1150/230\\I=5[amp]](https://tex.z-dn.net/?f=1150%3D230%2AI%5C%5CI%3D1150%2F230%5C%5CI%3D5%5Bamp%5D)
A 15 [amp] fuse must be used. Always the fuse must be larger than the operating current, to protect the equipment from very high currents. above 15 [amp]
All cells are living however organelles are not living there are no organisms that consist of just a single cell
For this problem, you would use the equation v=u+at. In this case, u=1 v=0 (when the object is at rest) a=-1
v=u+at
0=1+(-1)t
t=1 second