People have diffrent body builds and bone structure
A drag because the lift keeps it up and the drag brings it down
I think it would be 10 m/s
Answer:
t = 3.414 s
s = 23.3 m
Explanation:
Let t be the total time of motion
Let s be the total distance of motion
s - s/2 = ½at² - ½a(t - 1²) = ½a(t² - (t - 1)²)
s/2 = ½a(t² - (t² - 2t + 1)) = ½a(t² - t² + 2t - 1)
s = a(2t - 1)
s = 4(2t - 1)
s = 8t - 4
8t - 4 = ½4t²
8t - 4 = 2t²
0 = 2t² - 8t + 4
0 = t² - 4t + 2
t = (4 ±√(4² - 4(1)(2))) / 2 = (4 ± √8)/2 = 2 ± √2
t = 3.414 s
or
t = 0.5857... s which we ignore because it does not have a full last second.
s = ½(4)3.414² = 23.3137... 23.3 m
