Question

In the simple Bohr model of the eighth excited state of the hydrogen atom, the electron travels in a circular orbit around a fixed proton. The radius of the orbit is 4.28 ✕ 10−9 m, and the speed of the electron is 2.43 ✕ 105 m/s. The mass of an electron is 9.11 ✕ 10−31 kg. What is the force on the electron (in N)? (Enter the magnitude.)

Answer 1

Answer:

Net force on electron will be $12.568\times 10^{-12}N$            

Explanation:

We have given that the orbit $r=4.28\times 10^{-9}m$

Speed of the electron $v=2.43\times 10^5m/sec$

Mass of the electron is given as $m=9.11\times 10^{-31}kg$

Centripetal acceleration is given by $a_c=\frac{v^2}{r}=\frac{(2.43\times 10^5)^2}{4.28\times 10^{-9}}=1.3796\times 10^{19}m/sec^2$

Force is given by F = ma

So force $F=9.11\times 10^{-31}\times 1.3796\times 10^{19}=12.568\times 10^{-12}N$