I'm guessing "D" but I might be wrong
Answer:
y'=1/x
Step-by-step explanation:
![d/dx[ ln(u) ]=\frac{1}{u} *du\\y'=\frac{1}{cx} *c\\y'=\frac{1}{x}](https://tex.z-dn.net/?f=d%2Fdx%5B%20ln%28u%29%20%5D%3D%5Cfrac%7B1%7D%7Bu%7D%20%2Adu%5C%5Cy%27%3D%5Cfrac%7B1%7D%7Bcx%7D%20%2Ac%5C%5Cy%27%3D%5Cfrac%7B1%7D%7Bx%7D)
Hey! y is 100, x is 80.
hope this helped <3
First, arrange the data in a table for easy reference:
x y
20 50
30 45
45 55
60 70
80 80
90 90
45 80
120 100
90 95
70 85
Then, use the calculator to find the relationship of the two variables, x (minutes studied) and y (test scores)
The equation is
y = 0.56686x + 38.15
