4 years ago

PEOPLE PLZ HELP ME, MATH

Mathematics

1 answer:

masya89 [10]4 years ago

6 0

A. 125 is the answer to your question

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The slopes of perpendicular lines _____.

HACTEHA [7]

Hey there

The slopes of perpendicular lines are negative reciprocals. Perpendicular lines have slopes that are negative reciprocals of each other.

= (C)

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4 years ago

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How do i factor 9y cubed -15y square?

Tems11 [23]

Factor out the 3y²
3y²(3y-5)

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As shown in the diagram, a ship sails 16 nautical miles east from a harbor. It then sails 18 nautical miles in the direction of

Tresset [83]

The angle between the legs of length 16 and 18 has measure 90 + 55 = 145 degrees.

Now use the law of cosines: it says $d$ satisfies

$d^2=16^2+18^2-2(16)(18)\cos145^\circ$

and solving for $d$ gives

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4 years ago

Plzz help find value of following : 2sin75°.cos15°

polet [3.4K]

Answer:

$\frac{2+\sqrt{3} }{2}$

Step-by-step explanation:

Using the product to sum formula

sinxcosy = $\frac{1}{2}$ [ sin(x + y) + sin(x - y) ] , then

2sinxcosy = sin(x + y) + sin(x - y)

Given

2sin75°cos15° ← with x = 75 and y = 15 , then

= sin(75 + 15) + sin(75 - 15)

= sin90° + sin60°

= 1 + $\frac{\sqrt{3} }{2}$

= $\frac{2+\sqrt{3} }{2}$

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3 years ago

Solve for x. I’ll give points!

jeka57 [31]

Answer:

x = 5

explanation:

solving similarities:

bigger triangle is double of the smaller triangle.

balancing them:

→ x + 9 = 2(2x - 3)

→ x + 9 = 4x - 6

→ 4x - x = 9 + 6

→ 3x = 15

→ x = 5

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2 years ago

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