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3 years ago

Michael has $250. He increases his money by 25% and again by 10 %. What was the overall percentage increase in his money ?

Mathematics

1 answer:

valkas [14]3 years ago

8 0

Answer:

His money increased by 6.25, his overall percentage increase is 35

Step-by-step explanation:

250 x 0.25 x 0.10 = 6.25

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Please help me solve 8x+2y=32 and 10x-5y=-20

Tju [1.3M]

Answer:

(2,8)

x = 2

y = 8

Step-by-step explanation:

The steps are shown in the picture

7 0

3 years ago

5 1/2 + 3 4/5 + 1 1/4 =

ratelena [41]

Answer:

$10\frac{11}{20}$

Step-by-step explanation:

$5\frac{1}{2} + 3\frac{4}{5} + 1\frac{1}{4}$

1.Find the LCM(Least Common Multiple).

That would be 20.

2.Multiply so all denominators are equal.

$5\frac{10}{20} + 3\frac{16}{20} + 1\frac{5}{20}$

3. Add

$9\frac{31}{20}$

4. Simplify

$10\frac{11}{20}$

6 0

2 years ago

Pleas help me for 20 points

Montano1993 [528]

Answer:

240

Step-by-step explanation:

1 foot = 12 inches

4/3 feet = 16 inches

area = length × width

= 15 × 16

= 240 square inches

8 0

3 years ago

Which of the following represents a relation that is NOT a function? A. X 7 -5 10 -7 Y 34 32 40 34 B. X -7 -5 -7 2 Y 34 32 40 34

Nostrana [21]

The x-value of -7 shows up more than once in relation ...
B. X -7 -5 -7 2 Y 34 32 40 34

_____
When there is more than one y-value for an x-value, the relation is NOT a function.

8 0

4 years ago

Solving separable differential equation DY over DX equals xy+3x-y-3/xy-2x+4y-8

Ivanshal [37]

It looks like the differential equation is

$\dfrac{dy}{dx} = \dfrac{xy + 3x - y - 3}{xy - 2x + 4y - 8}$

Factorize the right side by grouping.

$xy + 3x - y - 3 = x (y + 3) - (y + 3) = (x - 1) (y + 3)$

$xy - 2x + 4y - 8 = x (y - 2) + 4 (y - 2) = (x + 4) (y - 2)$

Now we can separate variables as

$\dfrac{dy}{dx} = \dfrac{(x-1)(y+3)}{(x+4)(y-2)} \implies \dfrac{y-2}{y+3} \, dy = \dfrac{x-1}{x+4} \, dx$

Integrate both sides.

$\displaystyle \int \frac{y-2}{y+3} \, dy = \int \frac{x-1}{x+4} \, dx$

$\displaystyle \int \left(1 - \frac5{y+3}\right) \, dy = \int \left(1 - \frac5{x + 4}\right) \, dx$

$\implies \boxed{y - 5 \ln|y + 3| = x - 5 \ln|x + 4| + C}$

You could go on to solve for $y$ explicitly as a function of $x$ , but that involves a special function called the "product logarithm" or "Lambert W" function, which is probably beyond your scope.

8 0

2 years ago