Simplify 1/3n (-6+27m-51p)

Find the distance between (-8,7) and (13,-1)

grin007 [14]

Answer:

22.4722

Step-by-step explanation:

To answer this question we need to use the distance formula. The distance formula is as follows:

$d = \sqrt{(x2 - x1)^2+(y2 - y1)^2}$

Now, let's identify what each variable is:

x2 = 13

x1 = -8

y2 = -1

y1 = 7

Next, let's put these into the equation:

$d = \sqrt{(13 - (-8))^2 + (-1 -7)^2}$

Time to solve the equation:

$d = \sqrt{(21)^2+(-8)^2} \\d = \sqrt{441 + 64} \\d = \sqrt{505} \\d = 22.4722$

Therefore, the distance between the points of (-8,7) and (13,1) is 22.4722.

I hope this helps!!

- Kay :)

6 0

3 years ago

I need to graduate please. Which expression is a perfect cube? x^8 y^24 m^26 s^64

myrzilka [38]

Remember
$(a^b)^c=a^{bc}$

note that if $a^3$ is a perfect cube then $(a^3)^c$ is also a perfect cube when c is an integer

$(a^3)^c=a^{3c}$
so if a number is a perfect cube then the power must be divisible by 3

8 is not divisible by 3
24 is divisible by 3
26 is not divisibley by 3
64 is not divisible by 3

the perfect cube is y^24

8 0

3 years ago

An ice cream factory makes 120 quarts of ice cream in 2 hours. How many quarts could be made in 36 hours?

AlekseyPX

Answer:

2,160

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

a. Fill in the midpoint of each class in the column provided. b. Enter the midpoints in L1 and the frequencies in L2, and use 1-

Tresset [83]

Answer:

$\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1} & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7} & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}$

Using the frequency distribution, I found the mean height to be 70.2903 with a standard deviation of 3.5795

Step-by-step explanation:

Given

See attachment for class

Solving (a): Fill the midpoint of each class.

Midpoint (M) is calculated as:

$M = \frac{1}{2}(Lower + Upper)$

Where

$Lower \to$ Lower class interval

$Upper \to$ Upper class interval

So, we have:

Class 63-65:

$M = \frac{1}{2}(63 + 65) = 64$

Class 66 - 68:

$M = \frac{1}{2}(66 + 68) = 67$

When the computation is completed, the frequency distribution will be:

$\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1} & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7} & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}$

Solving (b): Mean and standard deviation using 1-VarStats

Using 1-VarStats, the solution is:

$\bar x = 70.2903$