Question

write the equation of a line that is perpendicular to the given kine and that passes through the given point. -x+5y=14;(-5, -2)

Answer 1

X + 5y = 14
5y = -x + 14
y = -1/5x + 14/5.....the slope here is -1/5. A perpendicular line will have a negative reciprocal slope. All that means is flip the slope and change the sign. So our perpendicular slope will be 5. See how I flipped -1/5 making it -5/1...and then changed the sign, making it 5.

y = mx + b
slope(m) = 5
(-5,-2)....x = -5 and y = -2
now we sub and find b, the y int
-2 = 5(-5) + b
-2 = -25 + b
-2 + 25 = b
23 = b

so ur perpendicular equation is : y = 5x + 23 <==