Answer:
infinitely many
Step-by-step explanation:
i can have a rectangle whose length is extremely close to 0 (ie 1 X 10⁻⁴⁴⁴⁴⁴⁴⁴⁴)
and have an extremely wide width. But it's still a rectangle that has perimeter 60.
Answer:
The answer is 
Step-by-step explanation:
You wanna simplify the expression first
5(3m+2p+m)
=15m+10p+5m
so B would be correct
To solve the question we shall use the formula for the range given by:
Horizontal range, R=[v²sin 2θ]/g
plugging in our values we get:
500=[160²×sin 2θ]/10
5000=160²×sin 2θ
0.1953=sin 2θ
thus:
arcsin 0.1953=2θ
11.263=2θ
hence:
θ=5.6315°~5.63
