How do I prove the corresponding angles theorem?

1 answer:

8 0

The Corresponding Angles Theorem states: If two parallel lines<span> are cut by a </span>transversal<span>, then the </span>pairs<span> of corresponding angles are </span>congruent.
A theorem is aproven<span> statement or an </span>accepted<span> idea that has been shown to be true.</span>

You might be interested in

10. Use the properties of exponents to simplify the expression:

aivan3 [116]

<h3><u>Answer</u> :</h3>

$\bigstar\:\boxed{\bf{\purple{x^{\frac{m}{n}}}=\orange{(\sqrt[n]{x})^m}}}$

Let's solve !

$:\implies\sf\:25^{\frac{3}{2}}$

$:\implies\sf\:(\sqrt[2]{25})^3$

$:\implies\sf\:5^3$

$:\implies\boxed{\bf{\red{125}}}$

<u>Hence, Oprion-D is correct</u> !

7 0

3 years ago

Pls help this is confusing :/

Aleksandr [31]

The coordinates of triangle U'V'W' include U'(8, 3), V'(4, -8) and W'(-8, -6) and this is represented by graph A shown in the image attached below.

<h3>What is a transformation?</h3>

A transformation can be defined as the movement of a point on a cartesian coordinate from its original (initial) position to a new location.

<h3>The types of transformation.</h3>

In Geometry, there are different types of transformation and these include the following:

Dilation

Reflection

Rotation

Translation

Based on the information provided, triangle UVW would be rotated counterclockwise through an angle of 270 degree at origin to produce triangle U'V'W', we have:

$\left[\begin{array}{ccc}0&1\\-1&0\end{array}\right]$

Therefore, the image of triangle UVW would be given by this matrix:

$\left[\begin{array}{ccc}0&1\\-1&0\end{array}\right]$ $\left[\begin{array}{ccc}-3&8&6\\8&4&-8\end{array}\right]$

Image = $\left[\begin{array}{ccc}8&4&-8\\3&-8&-6\end{array}\right]$

Based on the image above, we can logically deduce that the coordinates of triangle U'V'W' include U'(8, 3), V'(4, -8) and W'(-8, -6) and this is represented by graph A shown in the image attached below.

Read more on transformations here: brainly.com/question/12518192

#SPJ1